The Student Room Group

Scroll to see replies

Original post by Dreametuber
Does 1.77x10^-4 sound familiar to anyone- can’t remebe what question


Yea. I think I got that for a Ka value ... I think it’s the question following the pH graph cos Ka = [H+]
What was the equation for NaBr and sulphuric acid
Enthalpy of atomisation is the enthalpy change when one mole of gaseous monoatomic atoms are formed from the constituent element in its standard state, nd that is 0.5I2 (s) ----> I (g), therefore it was just 107
Original post by fopeadedeji
It was in the form 0.5I2—> I , so I don’t think so
I thought the bond angle was 86 degrees cos I thought you’re meant to take away from the original bond angle if there are lone pairs ????
Original post by cheesypizza
for ClF3- i remeber getting octahedral shape with bond angle 90
Oh so it was for that one! I was really unsure about that question
Original post by Nina_85262737
Yea. I think I got that for a Ka value ... I think it’s the question following the pH graph cos Ka = [H+]
Reply 65
thats what i thought
http://www.tutor-homework.com/Chemistry_Help/electronegativity_table/electronegativity.html
Original post by lollypenguin
wasn't the highest electronegativity krypton?
Original post by Dreametuber
What was the equation for NaBr and sulphuric acid


I think I got it wrong but:

2NaBr + H2SO4 ----> Br2 + SO2 + 2NaOH
I got:

2NaBr + H2SO4 ----> Na2SO4 + Br2 + H2O
Original post by Dreametuber
What was the equation for NaBr and sulphuric acid
Original post by Nina_85262737
I thought the bond angle was 86 degrees cos I thought you’re meant to take away from the original bond angle if there are lone pairs ????


I did that
I put that but I don’t think it was right
Original post by lollypenguin
I think I got it wrong but:

2NaBr + H2SO4 ----> Br2 + SO2 + 2NaOH
It was HBr + H2SO4 —> Br2 + SO2 + H2O

And the observation is red fumes of bromine gas
Original post by Dreametuber
What was the equation for NaBr and sulphuric acid
Square planar is 90, VSEPR gets weird there

Original post by Nina_85262737
I thought the bond angle was 86 degrees cos I thought you’re meant to take away from the original bond angle if there are lone pairs ????
thourghts on boundaries lower or higher?
I wrote 2NaBr +H2SO4 ->Br2 + SO2 + Na2O +H2O >.>

Brown Fume

Oxidising agent
Original post by lollypenguin
I think I got it wrong but:

2NaBr + H2SO4 ----> Br2 + SO2 + 2NaOH
Oh nooooooooo. Urgh. That’s so annoying. I see now :frown:
Original post by Uguuubear
Square planar is 90, VSEPR gets weird there
The amount of different answers I have seen to this question on TSR 😂😂😂
Original post by Uguuubear
I wrote 2NaBr +H2SO4 ->Br2 + SO2 + Na2O +H2O >.>

Brown Fume

Oxidising agent
Honestly they don't change very much each year, but they might be slightly lower considering how blessed last year's was in comparison
Original post by iamjosephvella
thourghts on boundaries lower or higher?
Electro spray is not in the specification?
Original post by CeliaaaWuuu
don't you need to multipying the 107 by 2? for the atomisation enthalpy change of iodine.

nope it was half
Reply 79
What was KW?

Latest

Trending

Trending