Mmhmm. Very few people do really well, very few people do really badly. The vast majority are bunched up in the middle, hence those sorts of boundaries.

Reply 24

Wenzel

HarisF1

So, what did you guys get for the first question?

Can't remember what numbers I got, but I know my method. I used distance/time to work out the speed, and put that into 0.5mv² to calculate the kinetic energy.

Then to work out the % used in breaking, I calculated the power (P=IV), multiplied that by 8 (car breaked for 8 seconds) and divided by the kinetic energy calculated in the first part; then just multiplied by 100.

Reply 25

GoinSideway

did the question ask specifically for the % ? or just the efficiency?

Reply 26

HarisF1

I got 30ms-1 for velocity, then 720000 for the kinetic energy

Then I got 1.2% as the efficiency.

percentage.

HarisF1

I got 30ms-1 for velocity, then 720000 for the kinetic energy

Then I got 1.2% as the efficiency.

Same.

I could not do the gravity questions about jupiter. Made a right hash of them. And couldn't remember the differences between the types of forces. But other that that I thought it was all good.

Reply 29

jam12

1

Wenzel

Can't remember what numbers I got, but I know my method. I used distance/time to work out the speed, and put that into 0.5mv² to calculate the kinetic energy.

Then to work out the % used in breaking, I calculated the power (P=IV), multiplied that by 8 (car breaked for 8 seconds) and divided by the kinetic energy calculated in the first part; then just multiplied by 100.

Yeh same as me. I just looked at the first question was like eh?? Finally found out u was 30ms though. What did you guys put for the written part.....the coil one.

Overall, that was a hard paper imo - much harder than last years where I thought 51 for an A was very generous. I missed out last questions, probs lost about 5 marks on the graph and also the capcitence questions about time etc. All in all, I think I won't be getting an A so am HOPING I can get a B to get into my insurance :frown:

.... otherwise i'm gonna be devastated.

Why this year, I mean mod 4 was ten times harder than previous years and so was the synoptic. Pfff.

Reply 30

GoinSideway

damn, i put the efficiency in decimal not %.... **** every single mark matters for me

Reply 31

cobra2

1

i cant remember for the percentage i think i put 4.8%, :s-smilie:

Reply 32

HarisF1

So far, it seems I'm correct in the ones i've written!

What about the forces on the coil?

I had no idea, so I made something up.

Reply 33

HarisF1

First time round, I got that.

Only 'cos I found the deceleration by s/t^2

Which was definitely wrong.

Reply 34

saxabojed

I used F=BQv for the coil, complete guess, said there was Magnetic Field from the magnet B, flux was being cut and rate of that induced charge/current Q and the thing was moving so had a velocity v, therefore meaing a force was produced. Which i said opposed the motion.

Very Very dodgey physics and probably wrong....

Reply 35

cobra2

1

the question at the end i fink, asks describe how quark stucture changes for the equation p + p = helium + positron + neutrino

is that equation right? and will i get the marks if i said that 2 up quarks fuse to form a up quark and down quark? (as 1 proton and 1 neutron in helium) :s-smilie:

or am i completely wrong?

Reply 36

*~#lightning*~#

HarisF1

I had no idea, so I made something up.

I did that on practically every question!
A few show that questions were good, but Im messed up most stuff.

Reply 37

HarisF1

I said something along those lines...

As a current passes through the coil, a magnetic force is induced which pushes against the permanent magnet, creating an opposing force.

Lol.

Reply 38

chidona

15

HarisF1

For the mass one,

Do g= Gm/r for both bodies.

g = G*1040 / r

and

g =G*1/ r

Thats it.

r is the value calculated in the earlier part (minus) The zero g distance for the sun, and the zero g distance for jupiter

It gives an answer like 0.03* 10^-34

Which is zero.

I actually derived the distance - I let 'd' be the distance from the zero potential to jupiter and then equated g(jupiter) and g(sun) letting R(jupiter) =d and R(sun) = (distance from jupiter to sun)-d
Do some fiddly bits and you get the 'd' as what they asked for.

Only part of that I couldn't do at all was 1 (b). Not a clue. Lenz's law? God knows what was going on with that question.

That said, I didn't really like the question with the power output and solar panel - where you had to calculate the area under the graph, which took forever. Also, I hate the box boundary on the graph question - made things slightly difficult. I got a value of 9.67 ish for 'g', so meh.

I got the feeling it was an ok paper, really made you think - last question, for example.

Reply 39

HarisF1

One of the Up quarks changes to a down quark, but that equation seems perfect to me. That's how I did it.

AQA(A) Physics Synoptic Paper PA10 - 17th June 2008

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