the organic product is going to be the one with the carbons and hydrogens and such. so in this case:
(a) CH3OH
(b) CH3CH2Cl
(c) CH3CH2OH
(d) CH3CH2CH=CH2
since it's a multiple choice, i'll show you a shortcut!
atom economy has the equation 'Mr of desired product/ sum of Mr of all products x 100' and so you're gonna be looking for a bigger number on top to maximise the percentage. in this case, you don’t need the desired mass, just Mr. already, looking at (d) the organic product is the bigger one of the two products, so you'll get a high percentage. you dont need to calculate the other ones once you spot this, as (a) has a relatively small organic product, (b) has many other products which decrease atom economy, and (c) is similar to (b). for d, you get:
(12 x 4) + (1 x 8) / (12 x 4) + (1 x 8) + 18 then x100 to get 75.68%, the highest atom economy.