Edexcel A Level Physics Paper 1: Advanced Physics I 9PH0 01 - 26 May 2022 [Exam Chat]

That was such a bad question I just said how diode conducts only in positive p.d so pd would not be alternating

Original post by Emily~3695

The bit about explaining how the diode thing worked it wasn’t to do with the capacitor part tho it was just the first part of the question.

Reply 42

Jo152001

1

Original post by studentLuna

Random question : how much did they stick to the advanced info? Just trying to get an idea for my biology Edexcel exam.

For the most part they stuck to it, the didn't cover ALL of the advanced info, there was some stuff missing. Although I can think of one question that was outside of what of the advanced info.

Reply 43

Haland

Did u guys do the power question at the start

Reply 44

wait everyone’s saying they got 50.8 how did u guys get that i got something rlly small 😭 i ended up doing tantheta= v^2/r / g no?

Reply 45

rowandxn

8

Original post by bleepo

wait everyone’s saying they got 50.8 how did u guys get that i got something rlly small 😭 i ended up doing tantheta= v^2/r / g no?

circular motion acceleration * mass is equal to the horizontal component of tension. you can then work out vertical component in terms of theta and mass and equal it to mg. masses cancel and solve for theta

Reply 46

irradiatedbatty

Original post by bleepo

wait everyone’s saying they got 50.8 how did u guys get that i got something rlly small 😭 i ended up doing tantheta= v^2/r / g no?

its tan(theta)=v^2/gr

Reply 47

Haland

Original post by bleepo

wait everyone’s saying they got 50.8 how did u guys get that i got something rlly small 😭 i ended up doing tantheta= v^2/r / g no?

I got tan as well

Reply 48

Emily~3695

15

Original post by bleepo

wait everyone’s saying they got 50.8 how did u guys get that i got something rlly small 😭 i ended up doing tantheta= v^2/r / g no?

I did tan theta is v^2/(rg) was your calculator in radians that might have been why you got a rly small answer

Reply 49

A.J.O

9

Original post by bleepo

wait everyone’s saying they got 50.8 how did u guys get that i got something rlly small 😭 i ended up doing tantheta= v^2/r / g no?

If you completed in radians, you might have got the same answer but in decimals. I did it and got like 0.6.. rads?

Reply 50

Original post by rowandxn

circular motion acceleration * mass is equal to the horizontal component of tension. you can then work out vertical component in terms of theta and mass and equal it to mg. masses cancel and solve for theta

Original post by irradiatedbatty

its tan(theta)=v^2/gr

yeah that’s the same thing as what i wrote

Reply 51

rowandxn

8

Original post by bleepo

yeah that’s the same thing as what i wrote

must be radians then 😭

Reply 52

Failure2022

Original post by RRAAAnn

literally

I am doomed

Reply 53

Original post by rowandxn

circular motion acceleration * mass is equal to the horizontal component of tension. you can then work out vertical component in terms of theta and mass and equal it to mg. masses cancel and solve for theta

wait so did you do Tcostheta = msg and Tsintheta = mv^2/r and then do you not divide by each other to get Tan? bc that’s what i did. and i don’t get 50.8 and also were you meant to measure from the picture cos it didn’t even say it was meant to scale 😭

Reply 54