Summations confusion
3n
∑ r(tan60r)
r=6
General formula = -n√(3)
What I've done is:
3n . . . . . . . . . 5
∑ r(tan60r) - ∑ r(tan60r)
r=1. . . . . . . . r=1
and i got -n√(3) - -(5/3)√(3)
But this seems to be wrong as the mark scheme gives it as -n√(3) -(-2√(3)) or rather -n√(3) + 2√(3)
I am lost.
∑ r(tan60r)
r=6
General formula = -n√(3)
What I've done is:
3n . . . . . . . . . 5
∑ r(tan60r) - ∑ r(tan60r)
r=1. . . . . . . . r=1
and i got -n√(3) - -(5/3)√(3)
But this seems to be wrong as the mark scheme gives it as -n√(3) -(-2√(3)) or rather -n√(3) + 2√(3)
I am lost.
(edited 10 months ago)
Original post by mqb2766
A bit hard to read, but I guess they want you to think about what happens for r=6.
Note it helps to post an image or ... of the original question and your working.
Note it helps to post an image or ... of the original question and your working.
Soz here's the question. I threw my phone away so I can focus on my revision so I can't take a picture of my working out with my 360p half working camera but all I've done so far was split the summation into the general formulas for 1 up to 3n minus 1 up to 5
edit: oops didnt mean to attach the practice paper but hey extra revision for whoever sees this
(edited 10 months ago)
Original post by stinkfartpc
Soz here's the question. I threw my phone away so I can focus on my revision so I can't take a picture of my working out with my 360p half working camera but all I've done so far was split the summation into the general formulas for 1 up to 3n minus 1 up to 5
Soz here's the question. I threw my phone away so I can focus on my revision so I can't take a picture of my working out with my 360p half working camera but all I've done so far was split the summation into the general formulas for 1 up to 3n minus 1 up to 5
Ok, so did you think about r=6 and why they put 3k as the upper summation limit?
(edited 10 months ago)
Original post by mqb2766
Ok, so did you think about r=6 and why they put 3k as the upper summation limit?
Yeah I saw how that would lead to adding 2sqrt3 but I don't understand why it wouldn't be adding 5/3sqrt3 if its 6 up to 3n
Original post by stinkfartpc
Yeah I saw how that would lead to adding 2sqrt3 but I don't understand why it wouldn't be adding 5/3sqrt3 if its 6 up to 3n
Can you have a fractional k, so if the upper limit was 1, so k=1/3, does the summation result hold?
Original post by mqb2766
Can you have a fractional k, so if the upper limit was 1, so k=1/3, does the summation result hold?
Ohhh ok I see now, thank you
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