As per the previous post add the zeroth term 2*0 + 1 = ... onto the result of the normal sum which starts at r=1. Simple as that as the sum is zeroth term + first term + ... + third term
Just a quick question, what do you do when r = 0? (the number below the sigma symbol)
Just started year 12.. btw!
Hello Jenius, Welcome to year 12! Regarding your question, when r = 0, the term inside the sigma notation is undefined. This is because the sigma notation tells us to add up all the terms from r = 1 to n, and 0 is not included in this range.
So, when r = 0, we simply ignore the term Thank you
Hello Jenius, Welcome to year 12! Regarding your question, when r = 0, the term inside the sigma notation is undefined. This is because the sigma notation tells us to add up all the terms from r = 1 to n, and 0 is not included in this range.
So, when r = 0, we simply ignore the term Thank you
As per the previous post add the zeroth term 2*0 + 1 = ... onto the result of the normal sum which starts at r=1. Simple as that as the sum is zeroth term + first term + ... + third term
Its easy to get confused by notation, but if youre unsure about a summation question with slightly unusual starting/end points, its always worth simply writing it out the individual terms as a sum//series for a few values.
Hello Jenius, Welcome to year 12! Regarding your question, when r = 0, the term inside the sigma notation is undefined. This is because the sigma notation tells us to add up all the terms from r = 1 to n, and 0 is not included in this range.
So, when r = 0, we simply ignore the term Thank you