I'm having trouble with part a of this question.
An elastic string PA has natural length 0.5m and modulus of elasticity 9.8 N. The string PB is inextensible. The end A of the elastic string and the end B of the inextensible string are attached to two fixed points which are on the same horizontal level. The end P of each string is attached to a 2kg particle. The particle hangs in equilibrium below AB, with PA making an angle of 30° with AB and PA perpendicular to PB. Find:
a the length of PA (7 marks)
b the length of PB (2 marks)
¢ the tension in PB. (2 marks)
Looking at the mark scheme, surely, since cos uses CAH, the hypotenuse T1 should = 2g over cos60?
Am I being stupid or is this just an error in the textbook?
Mark Scheme: Question 10, Page 3 -
https://www.activeteachonline.com/default/player/document/id/725771/external/0/uid/357726