The Student Room Group

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Reply 1
Should be correct:

1. i) α = 3+ j
β = 3- j
ii) α =√10 (cos0.322 + jsin0.322)
β =√10 (cos-0.322 + jsin-0.322)
2. A=2, B=1, C=5
3. i) P= ((2 1)¦(0 2))
ii) A’’ = (4,0), B’’ = (4,6), C’’ =(0,6)
iii) stretch parallel to x-axis factor 4, stretch parallel to y-axis factor 6
4 . arg(z-(2-2j)) = π/4
5. α=-2, p=-8, q=12
6. if required
7. if required
8. i) x=±√3, y=3/8
ii) x=-2,4, y=1
iii) both sections large and positive outside x =-2 and 4, with line crossing y=1 on the negative side before approaching y=1.
iv) -2<x&#8804;-&#8730;3, &#8730;3&#8804;x<4
9. i) &#945; + &#946; = 3, &#945;&#945;*= 2, (&#945;+beta)/&#945; =3/2 &#8211;(3/2)j
ii) z2 -2z +2 = 0
iii) A=-6,B=15,C=-18,D=10
10. ii) AB =42I [matrix shown]
iii) (1/42)B
iv) x =-3, y=2, z=-2
Woah nice, thanks! Did you sit this paper?
OMG, I have just seen a glaring awful error I made on the first question :frown:
I still think I did okay though, thanks again.
Reply 3
Yeah i did, went through it with a friend after. No problem :smile:
Dr. X
Yeah i did, went through it with a friend after. No problem :smile:

Wow, so do you think you got full marks?
I'm happy to see that most of my answers agree with yours. I made a stupid mistake on 1 ii) and forgot how to do the last part of 10 so that is about -7 marks. Apart from that though everything was fine.
Reply 5
You should not use jj to represent a complex number unless you are talking about engineering, which you are not.

You need to replace jj with ii and pronto :stomp:
Thoust&#8482
You should not use jj to represent a complex number unless you are talking about engineering, which you are not.

You need to replace jj with ii and pronto :stomp:

I know that i is the usual notation but if you were doing this exam you would know that MEI use j and not i.
Probably because it's Mathematics in Education and Industry so they like to emphasise the applied side.
I sat this too - got stuck on the induction question of all things, then ended up not having enough time to do the rest of the paper to my best ability, so I hope I've done OK... :s-smilie:
Reply 8
Exam was really nice in comparison to the horror that was FP2.

Although I ****** up on the locus question, as soon as I left the hall I realised I wrote down (-2j) instead of (-2-2j)!
Reply 9
snowrockandice
I sat this too - got stuck on the induction question of all things, then ended up not having enough time to do the rest of the paper to my best ability, so I hope I've done OK... :s-smilie:


I guess the key for the induction was noticing 46=2×31\frac{4}{6} = 2\times3^{-1}.
etp
I guess the key for the induction was noticing 46=2×31\frac{4}{6} = 2\times3^{-1}.

Hehe, I didn't notice that but still got it right.
I agree, compared to horrible FP2 it was nice.
Reply 11
yellowjacket
Hehe, I didn't notice that but still got it right.
I agree, compared to horrible FP2 it was nice.


Oh, I guess there was other methods! :P

I just hope S1 + S2 this Monday is more akin to FP1 than 2 :smile:
Reply 12
Dr. X
Should be correct:

1. i) &#945; = 3+ j
&#946; = 3- j
ii) &#945; =&#8730;10 (cos0.322 + jsin0.322)
&#946; =&#8730;10 (cos-0.322 - jsin0.322)
2. A=2, B=1, C=5
3. i) P= ((2 1)¦(0 2))
ii) A’’ = (4,0), B’’ = (4,6), C’’ =(0,6)
iii) stretch parallel to x-axis factor 4, stretch parallel to y-axis factor 6
4 . arg(z-(2-2j)) = &#960;/4
5. &#945;=-2, p=-8, q=12
6. if required
7. if required
8. i) x=±&#8730;3, y=3/8
ii) x=-2,4, y=1
iii) both sections large and positive outside x =-2 and 4, with line crossing y=1 on the negative side before approaching y=1.
iv) -2<x&#8804;-&#8730;3, &#8730;3&#8804;x<4
9. i) &#945; + &#946; = 3, &#945;&#945;*= 2, (&#945;+beta)/&#945; =3/2 –(3/2)j
ii) z2 -2z +2 = 0
iii) A=-6,B=15,C=-18,D=10
10. ii) AB =42I [matrix shown]
iii) (1/42)B
iv) x =-3, y=2, z=-2


Being pedantic, but I believe you're 1ii, is wrong?

iirc it has to be of the form r(cosα+jsinα)r(\cos\alpha + j\sin\alpha), what you have is r(cosαjsinα)r(\cos\alpha - j\sin-\alpha) which while I know is the same, I *think* they're quite picky.
Thoust™
You should not use jj to represent a complex number unless you are talking about engineering, which you are not.

You need to replace jj with ii and pronto :stomp:

can you stop informing everybody that you know a tiny bit about complex numbers. PLEASE. She's only a GCSE student by the way, and yet she seems to think she knows all
Reply 14
I really enjoyed this exam :yes: it wasn't hard at all
I got 4 as:
arg (z-2+2j) = 50 grads
but apart from that, the rest of my answers match dr. x's
Reply 16
doodinthemood
I got 4 as:
arg (z-2+2j) = 50 grads
but apart from that, the rest of my answers match dr. x's


it was π4\frac{\pi}{4}, definitely.
etp
it was π4\frac{\pi}{4}, definitely.

Yeah i got that too, 50 grads is the same.
Wow, I didn't know anyone actually used grads. I thought it was obsolete as a way of measuring/describing angles.
Dr. X
Should be correct:
5. &#945;=-2, p=-8, q=12


Argh I had a terrible time!

I got 100% on all past papers I practiced, but totally screwed this up!!

I couldn't factorise both induction questions, nerves I guess, but the non-standard result one was really hard!

And as for question 5, i got the same answer as Dr. X, but it is wrong! I inserted these values into the equation, and it doesn't come to 0, therefore either the root and/or the coefficients are wrong.

Reckon best case, I lost 6 marks (FAT Chance)
Worst case, 18.

Whaddya guys think the grade boundary will be?

I hope its low, say 52 / 72, because that is the hardest FP1 I've ever seen.
I'm sooo frustrated, I might've got the right answer to Q5, then scribbled it out!!

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