I've attempted this question but I'm not sure if what i've concluded is correct. Using the distance time equation:
s=td I've calculated that the wave will travel 66cm within a time interval of 2ms at a speed of
330ms−1. Then using the wave speed formula
v=f∗λ . I calculated the wavelength as being 16.5cm. Those parts that I have calculated I am confident with, now onto the second parts. The duration of the wave being 2ms means that there will be two separate wavefronts, and these wavefronts will have a distance separating them of
0.033cm. I calculated this distance by multiplying the wavelength (
16.5cm) by the duration (
2∗10−3s). Now, coincidentally, when you divide the wavelength (
16.5cm) by this distance of (
0.033cm) you get
5. That's where I've got to right now and I'm not sure if any of it is relevant, would you mind posting the markscheme so I could also have a look at it. Thanks