As others have pointed out, for any two vectors:
a⋅b=0⇒a⊥b since we have
abcosθ=0⇒θ=2πBut you should try to understand this intuitively (or graphically maybe).
If
u(t) is a unit vector, then its length can't change, by definition. So if it varies with time, only its angle can change. So let it turn through an angle
Δθ in time
Δt.
Now draw
u(t),u(t+Δt) as arrows of unit length originating from some point P. Then
Δu=u(t+Δt)−u(t) is the arrow from
u(t) to
u(t+Δt).
As
Δt→0,
Δu tends to make a right angle with the other two vectors more and more closely (draw diagram and label angles to see this - the angles in question are
2π−2Δθ), so the change of the unit vector is perpendicular to itself in the limit, and thus so is its rate of change, as that is simply
ΔtΔu, a vector divided by a scalar, which doesn't change the direction of the vector.