You've got to break the circuit down into bits you can handle.
What are really easy to handle are circuits containing nothing but resistors in series and nothing but resistors in parallel.
first the two resistors on the right hand side (3R and 6R)... those are a pair of resistors in parallel which can be replaced with a single resistor using the rule for parallel resistors. R
effective = (1/R1 + 1/R2)
-1now the circuit looks like this...
and you've got 3 resistors in series that you can replace with one...
which you know how to solve as 2 resistors in parallel