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Probably a simple answer to this...

Could somebody here please inform me how 2/(2^(8) is the same as 1/(2^(7)?

I can't seem to figure out any logical answer explaining how halving the numerator changers the exponent on the denominator by -1?

I'm sure i'm being an idiot here but I can't figure it out.
(edited 7 years ago)
Original post by Squire1998
Could somebody here please inform me how 2/(2^(8) is the same as 1/(2^(7)?

I can't seem to figure out any logical answer explaining how halving the numerator changers the exponent on the denominator by -1?

I'm sure i'm being an idiot here but I can't figure it out.


xaxb\frac{x^a}{x^b} = ....?

The opposite is xa×xb=xa+b x^a \times x^b = x^{a+b} if that helps. :h: (or think about what it means when b is negative)
(edited 7 years ago)
Reply 2
2/2^8 = 2/2x2x2x2x2x2x2x2

The 2 in the numerator cancels one of the 2's in the denominator hence:

1/2^7 = 1/2x2x2x2x2x2x2
Reply 3
Original post by tjena
2/2^8 = 2/2x2x2x2x2x2x2x2

The 2 in the numerator cancels one of the 2's in the denominator hence:

1/2^7 = 1/2x2x2x2x2x2x2


Ah, so I was being an idiot. Thanks! that's cleared it up.
Reply 4
Original post by Squire1998
Ah, so I was being an idiot. Thanks! that's cleared it up.


No worries. Good luck :smile:

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