Year 12s: what will be the first way you research your future options? >>

Take our quiz to find out what your revision personality is! >>

Year 12s: what will be the first way you research your future options? >>

Take our quiz to find out what your revision personality is! >>

Help !! Differentiation and integration

username2312801

How would you differentiate and integrate 8/√x ?
Also how would you integrate 6/x^2 ?

Thanks

Original post by nisha.sri

How would you differentiate and integrate 8/√x ?
Also how would you integrate 6/x^2 ?

Thanks

What have you got so far?

Hint: write the expressions in the form

a x ^ n

username2312801

OP

Original post by Tau

What have you got so far?

Hint: write the expressions in the form

a x ^ n

So for differentiating 8/√x i've got 8/x^3/2

Original post by nisha.sri

How would you differentiate and integrate 8/√x ?
Also how would you integrate 6/x^2 ?

Thanks

you know

\sqrt x = x^{1/2}

right?

username2312801

OP

Original post by 123Master321

you know

\sqrt[x] = x^{1/2}

right?

Yep

:smile:

Original post by nisha.sri

Yep

:smile:

are you still stuck?

Original post by nisha.sri

So for differentiating 8/√x i've got 8/x^3/2

Not quite. Do you know how to differentiate something like

3x^2

? Consider what rule you're using, and apply that to this question.

username2312801

OP

Original post by 123Master321

are you still stuck?

Yep because for 8/√x I've got 8/X^3/2 is that right ?

Original post by nisha.sri

How would you differentiate and integrate 8/√x ?
Also how would you integrate 6/x^2 ?

Thanks

\frac{8}{\sqrt{x}} = \frac{8}{x^\frac{1}{2}} = \frac{8}{1} \times \frac{1}{x^\frac{1}{2}} = 8x^{-\frac{1}{2}}

From here you can use the standard differentiation power rule. The rearranging is the same idea in the second question, then you can do the standard add 1 to the power and then divide by the new power rule.

(edited 7 years ago)

Original post by nisha.sri

Yep because for 8/√x I've got 8/X^3/2 is that right ?

No, not sure how you got there, try using

\frac{a}{x^n} = ax^{-n}

username2312801

OP

Original post by 123Master321

No, not sure how you got there, try using

\frac{a}{x^n} = ax^{-n}

Oh yes i know where i went wrong thanks :smile:

:smile:

How would you do 4√x

sqrx=x^1/2 so 4sqrx=4x^1/2

Then you differentiate accordingly

username2312801

OP

Thanks guys i've worked it out :smile:

:smile:

Original post by nisha.sri

How would you differentiate and integrate 8/√x ?
Also how would you integrate 6/x^2 ?

Thanks

Just rewrite them both using powers.
square root x = x^1/2
etc..

Also, just remember: 8/√x is = 8 * 1/√x
and dont forget the +C when integrating XD until you come to C2.

Quick Reply

Latest

Trending

Trending

Articles for you

Bmat: when it is, what it costs and how to prepare

Bmat: when it is, what it costs and how to prepare

What is an LLM and how could it benefit your career?

What is an LLM and how could it benefit your career?

Powerful questions business students forget to ask their career advisers

Powerful questions business students forget to ask their career advisers

Why I chose a law degree and what studying law was like

Why I chose a law degree and what studying law was like