Higher Maths 2012

Any help would be appreciated, im a little confused about how to prove that a given point lies on a circle with a given equation :confused:

put the x and y co-ordiantes from the given point into the given equation..work it out..if it ends up as 0 that point lies on the equation :biggrin:

Reply 381

charlottedinkle

anyone got any tips on staying calm during the higher maths exam tomorrow..i know everything and i know i can do everything but my problem in maths is that i panick :frown:

Reply 382

lapples

Original post by Shwi

would anyone be able to talk me through how to do question 6 in section two of the 2009 past paper, i keep getting the wrong answer :smile:

for part a) did you get 3.262x10^17
then part b) did you get 1.612 years?

Reply 383

hollieeilloh

2

Hey, this is only a multiple choice question, but could anyone please tell me how you do these style of questions?

I know the '+c' at the end is the y-intercept, so in this case (obviously from the diagrams) it's 4... but yeah, I have no idea what else to do?? Thank you :smile:

question yo.png19.5KB

Reply 384

member592149

11

About to embark on a 7 and a half our revision sesh. :lol:

Anyway, does anybody know how to get the limits for last question in 2008, paper 2? And can you use any of the lines to equate?

(edited 11 years ago)

Reply 385

member592149

11

Original post by hollieeilloh

Hey, this is only a multiple choice question, but could anyone please tell me how you do these style of questions?

I know the '+c' at the end is the y-intercept, so in this case (obviously from the diagrams) it's 4... but yeah, I have no idea what else to do?? Thank you :smile:

Well, because it is +4 it mus be A or C. Neither of these has roots, so you must do completing the square to work out where the turning point will be and then you'll have your answer. :smile:

Reply 386

charlottedinkle

does anyone know how to do this? could u explain it to me?

Reply 387

hollieeilloh

2

Original post by JaggySnake95

Well, because it is +4 it mus be A or C. Neither of these has roots, so you must do completing the square to work out where the turning point will be and then you'll have your answer. :smile:

Ahh okay that makes sense, thank you very much :smile:

Reply 388

lapples

Original post by hollieeilloh

Hey, this is only a multiple choice question, but could anyone please tell me how you do these style of questions?

I know the '+c' at the end is the y-intercept, so in this case (obviously from the diagrams) it's 4... but yeah, I have no idea what else to do?? Thank you :smile:

the 3x^2 means that it is a "smiley face" curve..... The coefficient of x tells you about what the graph is doing
is the correct answer B?

Reply 389

hollieeilloh

2

Original post by lapples

the 3x^2 means that it is a "smiley face" curve..... The coefficient of x tells you about what the graph is doing
is the correct answer B?

Nope, it's C aha :smile:

Reply 390

Kaaal

Just keep telling yourself that panicking and stressing is only gonna make your grade worse - that helps me

Reply 391

lapples

Original post by hollieeilloh

Nope, it's C aha :smile:

Oh well

Reply 392

member592149

11

Original post by lapples

Oh well

Can you help me with Paper 2, 2008, final questio? :smile:

Reply 393

lapples

Original post by Shwi

would anyone be able to talk me through how to do question 6 in section two of the 2009 past paper, i keep getting the wrong answer :smile:

I have worked it out :biggrin:

You need to divide your 0.43 by 100 as it is a percentage, not a rate :smile:

N= Noe^rt
N= 61(million)e^(0.016x14)
N= 61e^0.224
Therefore N= 76.3(million)

Then:
N=Noe^rt
10.2=5.1xe^0.0043t
10.2/5.1=e^0.0043t
ln2=lne^0.0043t
ln2=0.0043t (ln and ecancel each other out)

t=ln2/0.0043
Therefore t= 161.2 years

Hope that helps? :smile:

Reply 394

Sami'

12

Feeling quite confident for tomorrow, do the 2009 paper today and a bit on graphs/logs and i should be fine for tomorrow.

Reply 395

Sami'

12

Just go in with a positive atitude. You know what you're doing, just take your time and it should be fine.

Reply 396

lapples

Original post by JaggySnake95

Can you help me with Paper 2, 2008, final questio? :smile:

Find the points of intersection.
32-2x^2=14
2x^2=18
x^2=9
x=+and -3

32-2x^2=24
2x^2=8
x^2=4
x= +and-2

Because of symmetry integrate half the shaded area and then double your answer.

You should have an integral of 3(top) and 0(bottom) of (32-2x^2-14) dx = 36

Then an integral of between 2(top) and 0 (bottom) of (32-2x^2-24) dx = 10.7

This means that 36-10.7=25.3
Area = 2x25.3= 50.6 units²

Haha try that :colone:

(edited 11 years ago)

Reply 397

Emma_Lawrie

2008 sqp paper one questions 24, i keep getting the wrong answer :angry:

could somebody please show me their working...thanks :biggrin:

Reply 398

nnnn12

2

Original post by Darrenh800

I've never added attachments before so I hope this works but my teacher gave out a word document which had past paper questions for a certain topic. I've attached the topics which you say you found difficult as I find it useful to attempt these questions - hope it helps! :smile:

If anyone has another topic they need, just ask and I'll see if a word document has been made for it!

See on the exponential and logs file, would you happen to know how to do question 20 and 8? It's the first few questions they are. These are the questions I really struggle with :/

Reply 399

Bonzo10

Anybody able to do Heinemann book EX14K Q6? If you could help that'd be great!!

Higher Maths 2012

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