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Logs help!

Given that log₁₀(y+1) = 2-log₁₀x, express y in terms of x as simply as possible.

Not really even sure where to start with this?

I tried to separate the left hand side by doing log₁₀y x log₁₀1 is this right?

Reply 1

raheem94

Original post by Natalie21

\displaystyle log_{10}(y+1) = 2 - log_{10}x \implies log_{10}(y+1) + log_{10}x = 2 \implies log_{10}(x(y+1)) = 2

Now use the rule,

log_ac=b \implies a^b = c

yeah, excellent

Original post by raheem94

\displaystyle log_{10}(y+1) = 2 - log_{10}x \implies log_{10}(y+1) + log_{10}x = 2 \implies log_{10}(x(y+1)) = 2

Now use the rule,

log_ac=b \implies a^b = c

Thank you

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Logs help!

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