Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Indices

Below is a question on indices I'm stuck on.

Simplify the following

(8a^6b^3)^\frac{1}{3}

Here is my working out:

\sqrt[3]{8a^6b^3}

\sqrt[3]{8}=2

6-3=3
a^3
3-3=0

This gives the following as the answer:

2a^3

This answer is incorrect. Why is the answer wrong????? What have I done wrong??? :confused:

:confused:

:confused:

Thanks for any help provided.

Question: What's

\sqrt{2^2}

? 2-2=0, is it 1?

Or...

You have

a\cdot a\cdot a\cdot a\cdot a\cdot a

How much is 1/3 of the a's?

(edited 11 years ago)

(a^b)^c = a^{bc}

OP

Original post by aznkid66

Question: What's

\sqrt{2^2}

? 2-2=0, is it 1?

Or...

You have

a\cdot a\cdot a\cdot a\cdot a\cdot a

How much is 1/3 of the a's?

\sqrt{2^2}

=just 2

1/3 of the a's are just 2 of them.

OP

Original post by TenOfThem

(a^b)^c = a^{bc}

but 8 X 1/3=2.666.....

This is not just 2, so how is it a step forward?

OP

Original post by TenOfThem

(a^b)^c = a^{bc}

Oh, does this rule only apply for variables e.g. a, b, x etc?

OP

I understand now The answer is 2a^2b.
This is because:

The cube root of 8 gives 2

1/3 X 6=2 so there is a^2

1/3 X 3=1 so there is just b

Thanks a lot for helping me out. :smile:

:smile:

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