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C3 January 2013 25/01/2013

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Original post by Skaterkid



how would you do this someone!!! what values would you put into tan(a+b)


You would use the tan2A formula so A would be 22.5
Original post by Alex_1
Has anyone been taught how to do the half angle questions? Do we need to know that for our exams? I'm really starting to panic now :erm:


Don't stress :tongue: Its not much of a formula

the common one is just

sin2x = 2sinxcosx

1/2(sin2x) = sinxcosx

^^ half angle formula :tongue:
Reply 1782
Original post by MyNameIsRay
How do you differentiate these:
Sec kx
Cot kx
Cosec kx

is it:
ksec(kx)tan(kx)
-kcosec^2(kx)
-kcosec(kx)cot(kx)

(They're not on data sheet with k, only tankx is)

I have a question with y=e^(2x) sec(3x) and need to find dy/dx and not sure what to do for sec.
I know I can just make it e^(2x) / cos(3x) and use the quotient rule but I would rather learn this way ^^


Aren't the differentiation for cot sec and cosec in the formula booklet?? I think tan is also in there :-)

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Original post by Alex_1
Aren't the differentiation for cot sec and cosec in the formula booklet?? I think tan is also in there :-)

Posted from TSR Mobile


yes but only tan has in terms of "kx"
Reply 1784
Original post by Alex_1
Has anyone been taught how to do the half angle questions? Do we need to know that for our exams? I'm really starting to panic now :erm:


It's best to know them, although they can be worked out from the addition formulas.
sin2x=2sinxcosxsin2x=2sinxcosx

cos2x=cos2xsin2x=2cos2x1=12sin2xcos2x=cos^2x-sin^2x=2cos^2x-1=1-2sin^2x

tan2x=2tanx1tan2xtan2x=\frac{2tanx}{1-tan^2x}
Original post by This Excellency
I hope so! My teacher reckons it's easier than C3 but then again, he teaches maths for a reason. :rolleyes:

New hat :colone: Pimp hat? Rap star hat? Top hat?
I wish I could wear hats. I just look weird :tongue:

Haven't been doing any work either. I'm just watching Southland :tongue: We still have all of tomorrow morning to do some last minute prep.

Good luck to you too :h:

You going for the A*?


My teacher says that too :lol:
I wish it was a pimp hat... But no, just a boring winter beanie/beret thing :tongue: I look weird in hats too, hence why I faffed around with it for an hour :awesome:
Yeah, feels like I've done like 2402389 past papers this month. Not trusting myself to leave things till morning though, considering I slept in till 11am today hahah.
Yuuup I am :smile: Actually did C3 already last summer, but aiming for a very high UMS now to take the pressure off C4!

Original post by Bulbasaur
That's a relief! :tongue: C3 isn't exactly hard, it's just annoying.


Agree. It's all the graphs! :unimpressed:
(edited 11 years ago)
Original post by Jack_Smith
You would use the tan2A formula so A would be 22.5


how would I enter tan22.5 under tan^2
Original post by Skaterkid
how would I enter tan22.5 under tan^2

(tan(22.5))^2
Original post by Jack_Smith
(tan(22.5))^2


all of that equals to 1
Original post by Skaterkid
all of that equals to 1


Hope this helps:

We can prove this using the identity:
tan(2A)=2tan(A) / (1-tan^2 A)

We already know that tan 45 = 1
Let A =22.5 so that tan 2A = tan 45 = 1

tan(45)=2tan(22.5) / (1-tan^2 22.5)
1 =2tan(22.5) / (1-tan^2 22.5)
(1-tan^2 22.5) = 2tan(22.5)
(1-tan^2 22.5) = 2tan(22.5)
(tan^2 22.5) + 2tan (22.5) - 1 = 0
let tan 22.5 = x
x^2 + 2x - 1 = 0

x= -1+root 2 or -1-root 2

but we know from the tan graph that tan22.5 is positive.
tan 22.5 = -1 + root(2)
Original post by Jack_Smith
Hope this helps:

We can prove this using the identity:
tan(2A)=2tan(A) / (1-tan^2 A)

We already know that tan 45 = 1
Let A =22.5 so that tan 2A = tan 45 = 1

tan(45)=2tan(22.5) / (1-tan^2 22.5)
1 =2tan(22.5) / (1-tan^2 22.5)
(1-tan^2 22.5) = 2tan(22.5)
(1-tan^2 22.5) = 2tan(22.5)
(tan^2 22.5) + 2tan (22.5) - 1 = 0
let tan 22.5 = x
x^2 + 2x - 1 = 0

x= -1+root 2 or -1-root 2

but we know from the tan graph that tan22.5 is positive.
tan 22.5 = -1 + root(2)


thanks so much

negged??
(edited 11 years ago)
Reply 1791
I struggle to see where domains lie has anyone got any tips on how to deduce them? And ranges?


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Original post by Jack_Smith
X


Sorry if this is getting annoying now

in the solomon papers theres 52.5 how would you work it out since you cannot make it equal to tan45 I tried to double 52.5 and tan105 didnt work :s-smilie:
Original post by Skaterkid
Sorry if this is getting annoying now

in the solomon papers theres 52.5 how would you work it out since you cannot make it equal to tan45 I tried to double 52.5 and tan105 didnt work :s-smilie:


you can do tan ( 22.5 + 30) = root 3/3 :smile:
Original post by Mus1995
I struggle to see where domains lie has anyone got any tips on how to deduce them? And ranges?


Posted from TSR Mobile


i feel sketching the graph really helps :smile:
Original post by Skaterkid
Sorry if this is getting annoying now

in the solomon papers theres 52.5 how would you work it out since you cannot make it equal to tan45 I tried to double 52.5 and tan105 didnt work :s-smilie:


use the double angle formula for tan4x with 2x = 105 tan210 = tan30 = 1/root3
then rearrange the formula to work out tanx which is tan52.5
Reply 1796
Anyone know the average grade boundaries for C3?
Reply 1797
Original post by otrivine
will the answer be >0

the answer is <1
Reply 1798
Original post by Alex_1
Has anyone been taught how to do the half angle questions? Do we need to know that for our exams? I'm really starting to panic now :erm:


half angle has often appeared in c4 not c3 in the past papers so wonder if they would give a question about it this time around.:smile::eek:
Reply 1799
Original post by posthumus
Don't stress :tongue: Its not much of a formula

the common one is just

sin2x = 2sinxcosx

1/2(sin2x) = sinxcosx

^^ half angle formula :tongue:

the half angle formula is in the formula sheet rite?

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