C1 Maths Help

Substitute y=5 and x=1 into your answer for (a) and this will give you the value of the constant of integration.

Now substitute x=1 into your equation.

Thanks, 1 more sneaky question please

(a) Evaluate (6.25) to the power of -0.5

(b) Solve the equation
4 (to the power of) x = 2 (to the power of) x+3

Thanks

I'm getting fed up now!

(a) Write 6.25 as an improper (top heavy) fraction. Now negative powers tell you to take the reciprocal and a power of 0.5 means take the square root.

(b) Rewrite 4 as $2^2$ and apply the rules of indices.

is a 2/5

b x=3


Thanks for your help and sorry for annoying you with questions

I see, i just misread the question. The graph of y=(x-4)squared would move to the left 4 right?

.

These are the points I have got so far, correct: A(0,4), B(8/3,0), C(-6,0)
so following the formula I get 1/2(-6-0)0 which must be wrong because I just get 0?

The mark scheme somehow gets 1/2(8/3 - 6)4

Hi, I got this question in a past paper which seems to come up a lot - the area of a right-angled triangle on a graph. In the mark scheme it says "using 1/2(Xc - Xa)Yb" but I was never taught this formula! Using pythagoras gives me some funny answers so I believe the mark scheme but then I input the X and Y coords (I'm assuming the little letter signifies which coord) and I get a completely different answer from the mark scheme!

These are the points I have got so far, correct: A(0,4), B(8/3,0), C(-6,0)
so following the formula I get 1/2(-6-0)0 which must be wrong because I just get 0?

The mark scheme somehow gets 1/2(8/3 - 6)4

Could someone please explain this to me? I'm so confused and the exam is in two weeks, this has seriously thrown me back

Hey, I struggle with these too! I've found the only way I can do it is if I split them up into two right smaller triangles, but, that gets even harder when the co-ordinates are fractions.

I've never learnt your way either. There's a way using a "Determinant" which is on the mark scheme which looks good, but, confusing...

I presume that should say +6

Have you drawn a diagram

If, so you should be able to see the base of the triangle is the x-axis from -6 to 8/3 = 8/3+6 and the height is the y-axis up to 4

Area of a triangle = 1/2 base x height