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Finding the area of a difficult triangle

Hi all. I have the following problem. Point A has coordinates (2,8) point B(0,2) and point C(2,-2)
I cannot see how the triangle has an area of 10 square units.
Any help greatly appreatiated

You just use the half base times height equation.

A= 1/2 bh
= 1/2 x 10 x 2
= 10

Draw out the diagram so you can see the height and base on the triangle.

Posted from TSR Mobile

Original post by magpiemagpie46

Hi all. I have the following problem. Point A has coordinates (2,8) point B(0,2) and point C(2,-2)
I cannot see how the triangle has an area of 10 square units.
Any help greatly appreatiated

Ok, so, area of a triangle = 1/2 base x height.
I made a quick graph on powerpoint to show you what the triangle looks like. Image included.

So, base = 10
Height = 2

0.5(10) * 2 = 10. :smile:

:smile:

It ALWAYS helps to draw out the question if it is graph based. =)
It then shows you clearly what you have and what you need.

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