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as level discriminant question

hi, can anyone help me work out how to do this?:s-smilie:

find the value of a for which
x^2 -4x +a
is always positive
Reply 1
Original post by gingerxo
hi, can anyone help me work out how to do this?:s-smilie:

find the value of a for which
x^2 -4x +a
is always positive


Well for the curve to always be positive it must not touch or cross the x axis
Therefore it has no real roots


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Complete the square and see if you can spot anything.
Reply 3
Original post by 42meaningoflife
Complete the square and see if you can spot anything.


completing the square gets (x-2)^2 -2 +a?? i'm acc so confused lol
Reply 4
is a = 4 ?
Reply 5
As it's a discriminant question, you're looking at the b^2-4ac part of the quadratic formula. If the equation is always positive, b^2-4ac must be equal to 0.
Therefore, 4^2-4(1)(a)=0
Therefore 16-4a=0
Therefore 4a=16
Therefore a=4.
This should be the right answer if I've read you correctly (I'm sure I have!!) :smile:
Reply 6
Is zero positive ? Should a be greater than 4 ?

Posted from TSR Mobile
(edited 10 years ago)
Reply 7
Sorry, sorry - I did read you wrong you're right - it should be greater than 4!!
If you look at you're completing the square, you'll see that x=2 - this is actually the x coordinate of the minimum point. Therefore, b^2-4ac<0 as there are no real roots (you can tell because it doesn't cross the x axis).
Therefore, 4^2-4(1)(a)<0
Therefore 16<4a
Therefore a>4
As this is the case, does the question want a value for a or a set of values. If it wants a set of values, then this is you're answer. If it's wanting a specific value then I'm afraid I'm not too sure where to go from here.

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