Oxford MAT Test - 5th Nov 2014

Reply 580

Karoel

6

Original post by Rugzii

What is the best score to get on this paper?

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100?

Reply 581

TheFuture001

12

Okay. So I just did 2013, and I totally remember why I felt like total **** leaving that exam last year ^^' I'm hoping the difficulty was an anomaly, maybe 2013 was some sort of anniversary and the tutors were expecting to find some sort of hidden talent??

I'm gonna be the optimist I am and expect a paper similar to 2012. But if it isn't, well, I guess I'll have fun at Warwick xD ...

Reply 582

GorlimtheUnhappy

2

Hi guys,

if you have a sequence where the nth term is the (n-1)th term multiplied by some constant a then added by another constant b, is there a way to write the nth term in terms of n?

Reply 583

Krollo

17

Best of luck to everyone doing this :-)

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Reply 584

foxfire54

Original post by GorlimtheUnhappy

Hi guys,

if you have a sequence where the nth term is the (n-1)th term multiplied by some constant a then added by another constant b, is there a way to write the nth term in terms of n?

For a sequence where the first term is 1, the common ratio is a, and the added constant is b, then you get this sequence:
1
a+b
a²+(a+1)b
a³+(a²+a+1)b
a⁴+(a³+a²+a+1)b
and so on.
So the nth term would be something like a^n-1+(Σⁿ_r=2(a^r-2))b
There's probably something wrong with the coefficient of b, but I'm tired and I need to rest for tomorrow.
Why do you ask, anyway?

(edited 9 years ago)

Reply 585

RichE

15

Original post by AwesomeSauce#1

For 5 (vi) I don't understand why.

Understand why what? If you're going to be so terse it's hard to know how to reply.

Reply 586

ThatPerson

18

Original post by Karoel

I think it's the input to the function that confuses me, but I'm slowly getting the hang of it. In this example, does the dash in g'(x + 1) imply a derivative with respect to x or to x+1?

They also like asking questions like this one, but they're a bit more manageable. I think these ones are more about finding a general pattern.

With respect to x.

I found that question quite hard actually, and I couldn't come to an answer via mathematical methods. I had to use a bit of logical reasoning to see that there would be more +1 numbers than -1, but that the difference between them wouldn't exceed 50 (hence 28).

(edited 9 years ago)

Reply 587

AwesomeSauce#1

11

Original post by RichE

Understand why what? If you're going to be so terse it's hard to know how to reply.

Lol sorry, I meant, why turn it 90 degrees at all? Because I never would have thought of that.

Reply 588

ThatPerson

18

Has anyone else done 2002 Q5?

I got i) a & c wrong. I looked at the solution DFranklin posted on the solutions thread, but I didn't understand his method/how he thought about it to come to that answer.

I am really not a fan of combinatorics or counting questions.

(edited 9 years ago)

Reply 589

CD223

10

Anyone else really not have a good feeling about this?

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Reply 590

Rrussell1

2

Would anyone mind explaining 2009 1h for me? I don't understand how they simplify the result from the trapezium rule, I thought it was a geometric series but I don't think I got the right result.

Reply 591

RichE

15

Original post by AwesomeSauce#1

Lol sorry, I meant, why turn it 90 degrees at all? Because I never would have thought of that.

It's in the program. You do P_n and it moves you a certain vector, you then do a 90 degree turn and then do P_n again.

Reply 592

Light_bulb

8

I shall sleep for 4 days and 3 nights after the MAT tomorrow.

Reply 593

ThatPerson

18

Original post by Rrussell1

Would anyone mind explaining 2009 1h for me? I don't understand how they simplify the result from the trapezium rule, I thought it was a geometric series but I don't think I got the right result.

It is a geometric series. What is your last term?

Reply 594

DomStaff

2

Original post by M.green

Ok I don't mind if you reply me later, I can't find the largest value of Q in all of the parts

It is just the point that is a tangent of x+y=k, for the largest possible k. Obviously, this will be at (1/root2, 1/root2). Same applies for xy=k

Reply 595

Slowbro93

20

Best of luck for everyone doing this tomorrow. :h:

Reply 596

DomStaff

2

I don't even know why I care about this exam so much, only doing it for Imperial not Oxford. Yet I have a strong desire to beat most Oxford applicants and get in the 90s...who says sports don't make you competitive?

Having said all this, with the current style of paper, 90s is rather improbable.

Reply 597

Noble.

17

Everyone have a look at this post here: http://www.thestudentroom.co.uk/announcement.php?f=373&a=1469

Do not discuss the exam until Thursday 5pm GMT. All you're going to do by talking about it before then is move up the boundaries for an interview and offer :lol:

Reply 598

username1162972

18

Original post by DomStaff

I don't even know why I care about this exam so much, only doing it for Imperial not Oxford. Yet I have a strong desire to beat most Oxford applicants and get in the 90s...who says sports don't make you competitive?

Having said all this, with the current style of paper, 90s is rather improbable.

Yep cambridge>oxford we will show them how its done

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Reply 599

Noble.

17

Original post by DomStaff

I don't even know why I care about this exam so much, only doing it for Imperial not Oxford. Yet I have a strong desire to beat most Oxford applicants and get in the 90s...who says sports don't make you competitive?

Having said all this, with the current style of paper, 90s is rather improbable.

Don't be ridiculous, it's not that difficult to get 90 :tongue:

Oxford MAT Test - 5th Nov 2014

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