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AQA A2 Statistics 2 MS2B Unofficial Mark Scheme

Poll

What do you think will be the raw mark for an A* (90UMS)

These are my answers from the Statistics 2 exam this morning :smile: Hope it went well!
1. Poisson Distribution
a) P(X=<5) = 0.935 (2 Marks)
b) P(X=2) = 0.119 (3 Marks)
c) Parameter/Mean = 15
P(12 =< X <18) => P(X=< 17) - P(X=<11) = 0.564 (4 Marks)
2. Rectangular Distribution
a) k=b-a (1 Mark)
b) i) a=-2 b=4 (4 Marks)
ii) Out of 4, the probability of one being negative can be calculated using binomial
= 4C1 * (1/3) * (2/3)^3 = 0.395 (3 Marks)
3.
a)
i) Assuming that the standard deviation is 2 => Use Z value to calculate confidence interval = (907.7, 910.7) (4 Marks)
ii) As the standard deviation is unknown, use s as an unbiased estimate for the standard deviation => Use T to calculate the confidence interval = (907.2, 911.2) (4 Marks)
b) Inspector has a concern about weight of bags being less than 907 (2 Marks)
4. a) No (1 Mark)
b) Reject the H0, Mean is less than 44.1 (8 Marks)
c) i) Explain Type 1in context (2 Marks)
ii) explain Type 2 in context
5.
a) Chi-Squared = 7.053, 7.053>5.991 so Reject H0 (9 Marks)
b) The belief is likely correct (1Mark)
6.
a) 0.17 (2 Marks)
b) Show f(x) = (1/2) - (1/8)x (1 Mark)
c) i) E(X) = 4/3 (3 Marks)
ii) E(X^2) = 8/3 => Var(X) 8/9 (4 Marks)
d) E(Y) = 2 Var(Y) = 8 (2 Marks)
7.
a) show a=0.180 using Poisson Distribution, and b=0.143 as the sum of all the probabilities = 1 (3 Marks)
b) E(X) = 2.925 E(X^2) = 10.113 => SD = 1.25 (5 Marks)
c) 1.89 pounds (2 Marks)
d) Using 4 => 2.17 pounds, therefore more profit will be made by stocking 4 (5 Marks)

Credit to Lau14 for Mark Allocations :smile:
(edited 8 years ago)

Scroll to see replies

Reply 1
What do think the grade boundaries will be? Do you agree that this was harder than last year? I think so.
Reply 2
Original post by a123a
What do think the grade boundaries will be? Do you agree that this was harder than last year? I think so.


I think it was harder, not sure what the boundaries will be, but I am pretty certain they will be lower than last years :smile:
Reply 3
Original post by jjsnyder
I think it was harder, not sure what the boundaries will be, but I am pretty certain they will be lower than last years :smile:


I would hope so!
Reply 4
6b was show f(x) = blah blah from F(x)
Reply 5
Original post by Red Fox
6b was show f(x) = blah blah from F(x)


Thanks :smile:
Reply 6
I think that it was harder!

How many ums do you think will 56 be?
Reply 7
Original post by majka
I think that it was harder!

How many ums do you think will 56 be?


I of course cannot tell you for certain, but probably about 72 UMS
Reply 8
4b?
Reply 9
Original post by majka
I think that it was harder!

How many ums do you think will 56 be?


Likely around the 70 region, S2 usually has fairly high boundaries and while they should be lower than last year I don't know that they'll drop massively!
can someone show worked solutions for 7c&d think thats where I dropped marks but want to see how many
(edited 8 years ago)
Reply 11
I think I might need to subscribe to Statistics Weekly..
Reply 12
Original post by HeyC97
I think I might need to subscribe to Statistics Weekly..


I did nearly laugh when I came across that in the exam, such subtle naming!
Got all of those answers :biggrin:. Although I don't know why one of the answers (I think for the assumption question) is "No".
Original post by HeyC97
I think I might need to subscribe to Statistics Weekly..


I'm the regular customer! :biggrin:


JK I hate stats...
Reply 15
Original post by PrimeLime
I'm the regular customer! :biggrin:


JK I hate stats...


I used to, but I am starting to like it now, might do S3 next year :smile:
On the last question how were we supposed to go about finding a?

I didn't really get the context of the question :/
Reply 17
What was question 4 about? Can't remember lol
Original post by jjsnyder
I used to, but I am starting to like it now, might do S3 next year :smile:


:afraid: S3... oh god...
I only get a one year break from stats unfortunately. :frown:
On the plus side, it means a year of almost only mechanics and pure :biggrin:. Like 4 pure modules and 5 mechanics modules...
Original post by ibanezmatt13
On the last question how were we supposed to go about finding a?

I didn't really get the context of the question :/


the extra sales were poisson distribute with a mean of 2, a was the probability of selling 4, which is 3 extra sales, so (e^-2)(2^3)/3! = a

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