The Student Room Group

How to solve this?

I know I'm posting a lot at the moment, but I'm genuinely so confused and don't really know how else to find help.

I have this equation:

P=3
Q=2
R=1/2

p^3 x q^5 x r ^6

So it's obviously 3^3 x 2^5 x 1/2^6

So 3 x 2 x 1/2 is 3 add the powers surely it'd be 3^14 but it's not?

So I tried a different approach of raising each number to its power before multiplying and it still came out with the wrong answer, where am I going wrong?
Reply 1
Original post by theoallen
I know I'm posting a lot at the moment, but I'm genuinely so confused and don't really know how else to find help.

I have this equation:

P=3
Q=2
R=1/2

p^3 x q^5 x r ^6

So it's obviously 3^3 x 2^5 x 1/2^6

So 3 x 2 x 1/2 is 3 add the powers surely it'd be 3^14 but it's not?

So I tried a different approach of raising each number to its power before multiplying and it still came out with the wrong answer, where am I going wrong?


Is this Core Math-2 A Level?
Reply 2
Original post by IAROX15
Is this Core Math-2 A Level?


No, B1 Aircraft Engineering licence!
It's (3x3x3) x (2x2x2x2x2) x ((1/2)(1/2)(1/2)(1/2)(1/2)(1/2)).


For (1/2)^6 you can do:

(1/2)^6 = (1^6) / (2^6) = 1/64.
(edited 7 years ago)
Reply 4
The answer is 13.5.
As person above has said, work out powers before multiplying.
So it would be 27 x 32 x 1/64 = 13.5
Reply 5
Original post by AnIndianGuy
BIDMAS. Powers must be dealt with first before multiplying. So raise each term so its power.


Thank you, I had a number wrong which was why I was getting an incorrect answer!

Quick Reply

Latest