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# How to solve this?

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1. I know I'm posting a lot at the moment, but I'm genuinely so confused and don't really know how else to find help.

I have this equation:

P=3
Q=2
R=1/2

p^3 x q^5 x r ^6

So it's obviously 3^3 x 2^5 x 1/2^6

So 3 x 2 x 1/2 is 3 add the powers surely it'd be 3^14 but it's not?

So I tried a different approach of raising each number to its power before multiplying and it still came out with the wrong answer, where am I going wrong?
2. (Original post by theoallen)
I know I'm posting a lot at the moment, but I'm genuinely so confused and don't really know how else to find help.

I have this equation:

P=3
Q=2
R=1/2

p^3 x q^5 x r ^6

So it's obviously 3^3 x 2^5 x 1/2^6

So 3 x 2 x 1/2 is 3 add the powers surely it'd be 3^14 but it's not?

So I tried a different approach of raising each number to its power before multiplying and it still came out with the wrong answer, where am I going wrong?
Is this Core Math-2 A Level?
3. BIDMAS. Powers must be dealt with first before multiplying. So raise each term so its power.
4. (Original post by IAROX15)
Is this Core Math-2 A Level?
No, B1 Aircraft Engineering licence!
5. It's (3x3x3) x (2x2x2x2x2) x ((1/2)(1/2)(1/2)(1/2)(1/2)(1/2)).

For (1/2)^6 you can do:

(1/2)^6 = (1^6) / (2^6) = 1/64.
As person above has said, work out powers before multiplying.
So it would be 27 x 32 x 1/64 = 13.5
7. (Original post by AnIndianGuy)
BIDMAS. Powers must be dealt with first before multiplying. So raise each term so its power.
Thank you, I had a number wrong which was why I was getting an incorrect answer!

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