You are Here: Home >< Maths

Announcements Posted on
TSR's new app is coming! Sign up here to try it first >> 17-10-2016
1. Hi,
I am preparing for my exam next week. Unfortunately, I cannot get to the answers for question 11ii/iii/iv on the 2015 June paper. I have put the MS answers below:
(ii) -2x^2+10x-8 (2 marks)
(iii) 2.5 (4 marks)
(iv) 9 (4 marks)

Here is the question:

11
Two curves, S1 and S2 have equations y = x^2 - 4x + 7 and y = 6x - x^2 -1 respectively. The curves meet at A and at B.

GRAPH

Points P and Q lie on S2 and S1 between A and B. P and Q have the same x coordinate so that PQ is parallel to the y-axis.

(ii) Find an expression, in its simplest form, for the length PQ as a function of x. [2]
(iii) Use calculus to find the greatest length of PQ. [4]
(iv) Find the area between the two curves. [4]

Does anyone have any clues???
Thanks
2. (Original post by EBworkin)
Hi,
I am preparing for my exam next week. Unfortunately, I cannot get to the answers for question 11ii/iii/iv on the 2015 June paper. I have put the MS answers below:
(ii) -2x^2+10x-8 (2 marks)
(iii) 2.5 (4 marks)
(iv) 9 (4 marks)

Here is the question:

11
Two curves, S1 and S2 have equations y = x^2 - 4x + 7 and y = 6x - x^2 -1 respectively. The curves meet at A and at B.

GRAPH

Points P and Q lie on S2 and S1 between A and B. P and Q have the same x coordinate so that PQ is parallel to the y-axis.

(ii) Find an expression, in its simplest form, for the length PQ as a function of x. [2]
(iii) Use calculus to find the greatest length of PQ. [4]
(iv) Find the area between the two curves. [4]

Does anyone have any clues???
Thanks
What have you tried for both questions?
3. maybe for iii maximum and minimum??? I'm clueless I'll come back to you If I get any answers
4. I know this exam is already over (did it earlier today), but just for my personal peace of mind -

I don't know ii, but for iii you find the maximum/minimum points of the two curves, then find the distance between these two points. You do this by differentiating the two curves to find their gradient functions, making this equal to 0 and solving the equation to give an x value for each curve. Then substitute this back into the original equation to give the y value of the coordinate. iv is asking you to integrate between A and B, subtracting the smaller from the larger value to find the area encompassed by the two curves.

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: June 6, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### How does exam reform affect you?

From GCSE to A level, it's all changing

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read here first

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams