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det(D) = \left| \begin{array}{ccc}1 & 1 & 1 \\a & b & c & a^2 & b^2 & c^2 \end{array} \right| = 0 \\ \\[br] [br]\therefore (b - c)(c - a)(a - b) = 0
\left| \begin{array}{cc} b & c & b^2 & c^2 \end{array} \right| - \left| \begin{array}{cc} a & c & a^2 & c^2 \end{array} \right| + \left| \begin{array}{cc} a & b & a^2 & b^2 \end{array} \right| = 0 \\ \\[br][br]\therefore bc^2 - cb^2 - ac^2 + ca^2 + ab^2 - ba^2 = 0
det(D) = \left| \begin{array}{ccc}1 & 1 & 1 \\a & b & c & a^2 & b^2 & c^2 \end{array} \right| = 0 \\ \\[br] [br]\therefore (b - c)(c - a)(a - b) = 0
\left| \begin{array}{cc} b & c & b^2 & c^2 \end{array} \right| - \left| \begin{array}{cc} a & c & a^2 & c^2 \end{array} \right| + \left| \begin{array}{cc} a & b & a^2 & b^2 \end{array} \right| = 0 \\ \\[br][br]\therefore bc^2 - cb^2 - ac^2 + ca^2 + ab^2 - ba^2 = 0
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Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71