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maths integration

hey does anyone know how to integrate -e^u
Reply 1
Original post by user493
hey does anyone know how to integrate -e^u


-e^u + c
if its with respect to u
Reply 2
Original post by mqb2766
-e^u + c
if its with respect to u

okay thanku, how come we don't divide by the u like -1/u e^u +c. or is that just the rule? thanks
Reply 3
Original post by user493
okay thanku, how come we don't divide by the u like -1/u e^u +c. or is that just the rule? thanks


The derivative of e^u with respect to u is e^u? If youre thinking of u(x) and the chain rule then the derivative
d e^(u(x)) / dx = du/dx e^u
Probably help to upload the original question?
(edited 11 months ago)
Reply 4
Original post by user493
okay thanku, how come we don't divide by the u like -1/u e^u +c. or is that just the rule? thanks

You divide through by the coefficient of u. So if it was -e^3u, the result would be -1/3 e^3u.
Reply 5
ty
Original post by moheat13
You divide through by the coefficient of u. So if it was -e^3u, the result would be -1/3 e^3u.
Reply 6
thanks makes sense
Original post by mqb2766
The derivative of e^u with respect to u is e^u? If youre thinking of u(x) and the chain rule then the derivative
d e^(u(x)) / dx = du/dx e^u
Probably help to upload the original question?

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