Logs help
Hey I don’t get how this is correct
If you simplify down you get…
ln2 - ln2^1/3
But idk what to do next
Ignore the other parts I’m just asking about the second line and how it becomes the last
And this too I got this answer but the actual is this… how??
If you simplify down you get…
ln2 - ln2^1/3
But idk what to do next
Ignore the other parts I’m just asking about the second line and how it becomes the last
And this too I got this answer but the actual is this… how??
(edited 11 months ago)
Original post by Matureb
Go back a line and remember that LN A - LN B = LN (A/B)
I get that but I still get wrong answer
And also check my edit
Original post by Alevelhelp.1
I get that but I still get wrong answer
And also check my edit
And also check my edit
Are you asking about the ln8?
(edited 11 months ago)
Original post by Alevelhelp.1
I get that but I still get wrong answer
And also check my edit
And also check my edit
Think about the 1/3ln8
Remember your indices knowledge as it is incredibly important.
You know that 8 = 2^3 right?
so 1/3ln8 = 1/3ln2^3
you move the 3 to the front and you get ln2
ln2 - 1/3ln2 = 2/3ln2
Original post by Heisenberg66
Are you asking about the ln8?
Yep…
ln8^1/3 - ln2^1/3
When I bring the 1/3 to the start I get…
1/3ln8- 1/3ln2
or if I just simplify I get ln2 -ln2^1/3
bht I can’t seem to get the correct form
Original post by Alevelhelp.1
Yep…
ln8^1/3 - ln2^1/3
When I bring the 1/3 to the start I get…
1/3ln8- 1/3ln2
or if I just simplify I get ln2 -ln2^1/3
bht I can’t seem to get the correct form
ln8^1/3 - ln2^1/3
When I bring the 1/3 to the start I get…
1/3ln8- 1/3ln2
or if I just simplify I get ln2 -ln2^1/3
bht I can’t seem to get the correct form
Yeah so you move the 1/3 to the front and you get ln(2) - 1/3ln(2) which is 2/3ln(2)
Original post by Heisenberg66
Yeah so you move the 1/3 to the front and you get ln(2) - 1/3ln(2) which is 2/3ln(2)
Ahh I see…
But…
In this question the first part (it’s correct btw)
But why is it not 1/2-1/2 which is zero…
And 32/16 which is 2
So wouldn’t it be 0ln2 which is just zero I don’t get why they didn’t do anything with the 1/2 at the start
Original post by Alevelhelp.1
Ahh I see…
But…
In this question the first part (it’s correct btw)
But why is it not 1/2-1/2 which is zero…
And 32/16 which is 2
So wouldn’t it be 0ln2 which is just zero I don’t get why they didn’t do anything with the 1/2 at the start
But…
In this question the first part (it’s correct btw)
But why is it not 1/2-1/2 which is zero…
And 32/16 which is 2
So wouldn’t it be 0ln2 which is just zero I don’t get why they didn’t do anything with the 1/2 at the start
You need to make sure the ln have the same base before subtracting them that way. So 1/2ln(32) - 1/2ln(16) cannot be zero because 32 and 16 are different numbers.
I would solve this by making it all in base 2. So you do the similar process to what I did before:
2^5 = 32
2^4 = 16
so 1/2ln(32) = 1/2ln(2^5) you move the 5 to the front just like you did before and you get 5/2ln(2).
Do the same process with the other number and you get 4/2ln(2)
so 5/2ln(2) - 4/2ln(2) = 1/2ln(2)
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