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A Level Maths Algebra and Functions

Hi, for part iii, how would I manipulate the modulus function when I put f(x) into g(x)?

Screenshot 2023-06-05 at 15.30.24.png
Reply 1
ii gives you the inverse of g, so why not use that? But not worked it through.
Reply 2
Original post by mqb2766
ii gives you the inverse of g, so why not use that? But not worked it through.

Sorry, how would I use the inverse of g?
Reply 3
Take inverse g of both sides so solve
f(x) = g^(-1)(31a)

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