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Trig Equation

I can't simplify this one:
sqrt (1+tan^A) / sqrt (1-sin^A)
could someone please help me?

((tanA)^2)+1=((secA)^2)

=>sqrt(((tanA)^2)+1)=secA (i)

AND

((sinA)^2)+((cosA)^2)=1

=>1-((sinA)^2)=((cosA)^2)=>sqrt(1-((sinA)^2))=cosA (ii)

(i)/(ii)=>secA/cosA=((secA)^2)

Newton.

Reply 2

BCHL85

Wow, I even don't understand the question ... what means by tan^A and sin^A.
What's your index?

Reply 3

Spoon

thanks Newton
i don't understand how secA/ cosA= (sec A)^2?
i get it secA/cosA to equal cosecA in the end?

just worked it out!

Spoon

thanks Newton
i don't understand how secA/ cosA= (sec A)^2?
i get it secA/cosA to equal cosecA in the end?

secA/cosA=(secA)(1/cosA)=(1/cosA)(1/cosA)=((1/cosA)^2)=((1/((cosA)^2))

=>=((secA)^2)

Newton.

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