Fine. But there is another question about isotopes: Why it is possible that there are atoms which have more neutrons than protons in a nucleus? in other words: How isotopes come into being?
Hi illusionz and Ari Ben Canaan, Thank you very much for your help indeed I really appreciated all the help you have given me
Illusionz can i just have confirmation for Spectra number 1 and number 5 please ? Especially number 5 because I cant understand from the post weather it is an amine or amide ? And can you tell me what bonds might be present in this spectra ? Thank you very much Lads
I think spectrum 1 is a hydrocarbon without a C=C, O, N etc It is possible there is a halogen but you really can't tell. You would need more data to determine the structure of the compound, NMR and mass spec would be very useful.
As for 5, I do not think it is an amide as an amide C=O is generally ~1680 wavenumbers, and in any case, almost certainly below 1700. The C=O in this case is above 1700 which gives me the impression the C=O and N-H are seperate functional groups and not part of an amide.
I think spectrum 1 is a hydrocarbon without a C=C, O, N etc It is possible there is a halogen but you really can't tell. You would need more data to determine the structure of the compound, NMR and mass spec would be very useful.
As for 5, I do not think it is an amide as an amide C=O is generally ~1680 wavenumbers, and in any case, almost certainly below 1700. The C=O in this case is above 1700 which gives me the impression the C=O and N-H are seperate functional groups and not part of an amide.
Mate for number 1 Can you tell me what would be reason for the hydrocarbon to not have the C=C and O, N having looked at the spectra ? Is it due to the peaks or something ?
Mate for number 1 Can you tell me what would be reason for the hydrocarbon to not have the C=C and O, N having looked at the spectra ? Is it due to the peaks or something ?
Because the spectrum doesn't have peaks in the regions these bonds cause peaks to appear.
Hey Everyone Can someone help me with a chemistry question
I need to draw just one mechanisms for
Nitration of Benzene Ethane + Bromine Ethane + Chlorine
Can someone help me draw these please
Thank you everyone xx
For the nitration of benzene you are essentially reacting H2SO4 and HNO3 together to produce a Nitronium ion.
Think about the interaction between the two acids.... Can you see a way by which a good leaving group (HINT: water) could be produced on the HNO3 molecule ?
For the nitration of benzene you are essentially reacting H2SO4 and HNO3 together to produce a Nitronium ion.
Think about the interaction between the two acids.... Can you see a way by which a good leaving group (HINT: water) could be produced ?
Right, So im essentially reacting : H2SO4 + HNO3 ----> Nitronium Ion ( Can you tell me the formula for this )
So after reacting H2SO4 + HNO3 would i expect to see water being produced ? Can you correct me if am going wrong, because chemistry is my weakest subject Also what bonding would i see in this mechanism ? xx
Right, So im essentially reacting : H2SO4 + HNO3 ----> Nitronium Ion ( Can you tell me the formula for this )
So after reacting H2SO4 + HNO3 would i expect to see water being produced ? Can you correct me if am going wrong, because chemistry is my weakest subject Also what bonding would i see in this mechanism ? xx
Are you an A Level student ?
I'm sure you are aware that the electrophile is NO2+ i.e. a nitronium ion.
Essentially, what happens is that the Nitric acid takes a proton from the Sulphuric acid to produce a good leaving group (water).
What is left is the NO2+ ion.
What follows is your usual electrophilic aromatic substitution reaction.
Here, have a look at this :
EDIT : The reaction equation is HNO3 + 2H2SO4 ---> 2HSO4- + NO2+ + H3O+
I'm sure you are aware that the electrophile is NO2+ i.e. a nitronium ion.
Essentially, what happens is that the Nitric acid takes a proton from the Sulphuric acid to produce a good leaving group (water).
What is left is the NO2+ ion.
What follows is your usual electrophilic aromatic substitution reaction.
Here, have a look at this :
EDIT : The reaction equation is HNO3 + 2H2SO4 ---> 2HSO4- + NO2+ + H3O+
Ah I see, it now makes sense I understand now that you've added a diagram in, and i can understand whats going on the reaction And yes i am doing a levels, its just i find chemistry a bit tricky
One thing I am confused about is what type of reaction is it ? Is it electrophilic aromatic substitution like you have stated above ? And what type of bonding is going on in this mechanism ? x
Ah I see, it now makes sense I understand now that you've added a diagram in, and i can understand whats going on the reaction And yes i am doing a levels, its just i find chemistry a bit tricky
One thing I am confused about is what type of reaction is it ? Is it electrophilic aromatic substitution like you have stated above ? And what type of bonding is going on in this mechanism ? x
The initial interaction between the two acids is a classic acid base reaction. Can you see how the Sulphuric acid donates a proton to the Nitric acid ? We then have a loss of water, which is secondary.
What follows is an electrophilic aromatic substitution.
The initial interaction between the two acids is a classic acid base reaction. Can you see how the Sulphuric acid donates a proton to the Nitric acid ? We then have a loss of water, which is secondary.
What follows is an electrophilic aromatic substitution.
Type of bonding ? What do you mean ?
Oh Right, So we first have an acid base reaction with a proton being donated to the nitric acid. Then a loss of water occours, which is secondary. Then electrophilic subsitution. I understand it now
Ben Canaan, I was asked in the question to analyse the type of reaction in each case in relation to its bonding. This is the part where i am confused on, Can you help me please ? x
I have discussed the fusion between Uranium and Deuterium in the physics society. During the discussion I have read that Uranium and Deuterium applies an energy bonding to become to Plutonium. Why energy come into being during the bonding between Uranium and Deuterium? I suppose that Uranium and Deuterium have to get a stimulated state to come to a bonding, as atoms keep the low-energy state by nature. And when atoms attend a bonding, they are stimulated. That is my supposition.
Name: Aleisha Cullen Hobbies : singing, sport listening to music studying: AS chemistry, RS, psyschology and English literature live: westmiddlands why i like chemo: its logical and interesting
hi could anyone give me some advice? Basically I am considering being a pharmacist but I don't know that much about it. What different things can a pharmacist do?
hi could anyone give me some advice? Basically I am considering being a pharmacist but I don't know that much about it. What different things can a pharmacist do?
Hey! You'd probably be better suited to looking around in and maybe starting a thread in this forum. You're more likely to get an informed reply there.
Hey! You'd probably be better suited to looking around in and maybe starting a thread in this forum. You're more likely to get an informed reply there.
thankyouu! I was trying to find the right place to post it!
Hey! You'd probably be better suited to looking around in and maybe starting a thread in this forum. You're more likely to get an informed reply there.
do you know what jobs I could go into with a chemistry degree?:P