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CCEA C3 May 2016

does anyone have a solution to qu 1 on the c3 june 2014 paper..
can't seem to get my head around it at the minute!!

The Simpson's Rule Question? This was actually a fairly straight forward Simpson's Rule question as you didn't need to calculate h as it's already given to you (3 metres).

Yo (first value) is 30m and Yn (last value) is also 30m
Y1 is 28, Y3 is 19, Y5 is 18.5, Y7 is 21 - these are your "odd y values"
Y2 is 22, Y4 is 16, Y6 is 20.8 - these are your "even y values"

The Simpson's Rule equation is given to you in the exams, and is h/3[(Yo+Yn)+4(Y1+Y3+Y5+Y7)+2(Y2+Y4+Y6)]. I always remember it as h/3[(first+last)+4(sum of "odd y values" )+2(sum of "even y values" )]

Your equation will be 3/3[(30+30)+4(28+19+18.5+21)+2(22+16+20.8)] = 523.6 = 524m^2 (Answer)

Hopefully this helps! I'm rubbish at explaining Maths. Dreading tomorrow's exam.