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IGCSE EDEXCEL MATHS PAPER 4H Unofficial Mark Scheme

2016 9th June PAPER 4H Mark Scheme
_______________________
1) 3n+4
2) 5.4
3) a) 388 (b) 395
4) a) 63 (b) 50 (c) 4 (d) 41 degrees = x (Hexagon)
5) a) m^7 (b) c^8 (c) a^15 (d) 10x+22
6) £456
7) 7,-1,2,7, Minimum Parabola
8) a) Enlargement, Scale Factor 2, Centre (1,0) (b) (-7,2) (7,-1) (10,-2) (c) (2,0), (1,0), (2,3)
9) 135
10) 60
11) (a) 97,000,000 (b) 1.4x10^8 (c) 1.08x10^9 (d) K=11
12) (a) 5.2 (b) 5
13) (a) M=0.25xp^3 (b) 31.25
14) x+5/2x+1
15) (a) 8x-1/15 (b) 2a^3e^2 (c) y=4.8
16) (a) 6/20, 4/20, 9/19, 6/19, 4/19, 10/19, 5/19, 4/19, 10/19, 6/19, 3/19 (b) 3/95 (c) 9/38
17) (a) 3 (b) 7 (c) x+5/2 (d) 4 or 1 = x
18) (a) 15 (b) 0.48 =12/25 Frequency density = frequency / width of interval
19) -5+12 Square Root[18]
20) Pi(300+100Square Root 2) = A
21) (a) In order from left to right, then down: (Set Theory)
4, 4, 6,
. 5,
6, . 2,
. 3
(b) 9/64
22) (a) MN = 2q-4p (b) PR = 0.5p+q (c) QR = 0.5p, OP = p
They are parallel because vectors are quantities which represent magnitude and directions, hence multiples of the same vector are parallel.
_____________________________________________________
(edited 7 years ago)

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Reply 1
12(b) was 9
No, it asked for ED not the total length, so it was 9-4, hence 5,
For part c of the final question, I believe you needed to state OP=2 QR or vice-versa to make it clear that you'd answered the question.
Original post by Sammy_Arab_KFA
2016 9th June PAPER 4H Mark Scheme
_______________________
1) 3n+4
2) 5.4
3) a) 388 (b) 395
4) a) 63 (b) 50 (c) 4 (d) 1
5) a) m to the power of 7 (b) c to the power of 8 (c) a to the power of 15 (d) 10x+22
6) £456
7) 7,-1,2,7, Minimum Parabola
8) a) Enlargement, Scale Factor 2, Centre (1,0) (b) (-7,2) (&,-1) (10,-2) (c) (2,0), (1,0), (2,3)
9) 135
10) 60
11) (a) 97,000,000 (b) 1.4x10 to the power of 8 (c) 1.08x10 to the power of 9 (d) K=11
12) (a) 5.2 (b) 5
13) (a) M=0.25xp to the power of 3 (b) 31.25
14) x+5/2x+1
15) (a) 8x-1/15 (b) 2a3e2 (c) y=4.8
16) (a) 6/20, 4/20, 9/19, 6/19, 4/19, 10/19, 5/19, 4/19, 10/19, 6/19, 3/19 (b) 3/95 (c) 9/38
17) (a) 3 (b) 7 (c) x+5/2 (d) 4 or 1 = x
18) (a) 15 (b) 0.48 =12/25 Frequency density = frequency / width of interval
19) -5+12 Square Root (18)
20) Pi(300+100Square Root 2) = A
21) (a) In order from left to right, then down: (Set Theory)
4, 4, 6,
. 5,
6, . 2,
. 3
(b) 9/64
22) (a) MN = 2q-4p (b) PR = 0.5p+q (c) QR = 0.5p, OP = p
_____________________________________________________


Original post by Sammy_Arab_KFA
2016 9th June PAPER 4H Mark Scheme
_______________________
1) 3n+4
2) 5.4
3) a) 388 (b) 395
4) a) 63 (b) 50 (c) 4 (d) 1
5) a) m to the power of 7 (b) c to the power of 8 (c) a to the power of 15 (d) 10x+22
6) £456
7) 7,-1,2,7, Minimum Parabola
8) a) Enlargement, Scale Factor 2, Centre (1,0) (b) (-7,2) (&,-1) (10,-2) (c) (2,0), (1,0), (2,3)
9) 135
10) 60
11) (a) 97,000,000 (b) 1.4x10 to the power of 8 (c) 1.08x10 to the power of 9 (d) K=11
12) (a) 5.2 (b) 5
13) (a) M=0.25xp to the power of 3 (b) 31.25
14) x+5/2x+1
15) (a) 8x-1/15 (b) 2a3e2 (c) y=4.8
16) (a) 6/20, 4/20, 9/19, 6/19, 4/19, 10/19, 5/19, 4/19, 10/19, 6/19, 3/19 (b) 3/95 (c) 9/38
17) (a) 3 (b) 7 (c) x+5/2 (d) 4 or 1 = x
18) (a) 15 (b) 0.48 =12/25 Frequency density = frequency / width of interval
19) -5+12 Square Root (18)
20) Pi(300+100Square Root 2) = A
21) (a) In order from left to right, then down: (Set Theory)
4, 4, 6,
. 5,
6, . 2,
. 3
(b) 9/64
22) (a) MN = 2q-4p (b) PR = 0.5p+q (c) QR = 0.5p, OP = p
_____________________________________________________


Original post by Sammy_Arab_KFA
2016 9th June PAPER 4H Mark Scheme
_______________________
1) 3n+4
2) 5.4
3) a) 388 (b) 395
4) a) 63 (b) 50 (c) 4 (d) 1
5) a) m to the power of 7 (b) c to the power of 8 (c) a to the power of 15 (d) 10x+22
6) £456
7) 7,-1,2,7, Minimum Parabola
8) a) Enlargement, Scale Factor 2, Centre (1,0) (b) (-7,2) (&,-1) (10,-2) (c) (2,0), (1,0), (2,3)
9) 135
10) 60
11) (a) 97,000,000 (b) 1.4x10 to the power of 8 (c) 1.08x10 to the power of 9 (d) K=11
12) (a) 5.2 (b) 5
13) (a) M=0.25xp to the power of 3 (b) 31.25
14) x+5/2x+1
15) (a) 8x-1/15 (b) 2a3e2 (c) y=4.8
16) (a) 6/20, 4/20, 9/19, 6/19, 4/19, 10/19, 5/19, 4/19, 10/19, 6/19, 3/19 (b) 3/95 (c) 9/38
17) (a) 3 (b) 7 (c) x+5/2 (d) 4 or 1 = x
18) (a) 15 (b) 0.48 =12/25 Frequency density = frequency / width of interval
19) -5+12 Square Root (18)
20) Pi(300+100Square Root 2) = A
21) (a) In order from left to right, then down: (Set Theory)
4, 4, 6,
. 5,
6, . 2,
. 3
(b) 9/64
22) (a) MN = 2q-4p (b) PR = 0.5p+q (c) QR = 0.5p, OP = p
_____________________________________________________

22b) it has to be a multiple of OP=p and it is 1/2p so it is parallel.
I think for part b of the Venn diagram question it was 5/9 and not 9/64, as it asked the probability of the students who both owned a desktop and a laptop to also have a tablet.
Original post by Sammy_Arab_KFA
2016 9th June PAPER 4H Mark Scheme
_______________________
1) 3n+4
2) 5.4
3) a) 388 (b) 395
4) a) 63 (b) 50 (c) 4 (d) 1
5) a) m to the power of 7 (b) c to the power of 8 (c) a to the power of 15 (d) 10x+22
6) £456
7) 7,-1,2,7, Minimum Parabola
8) a) Enlargement, Scale Factor 2, Centre (1,0) (b) (-7,2) (&,-1) (10,-2) (c) (2,0), (1,0), (2,3)
9) 135
10) 60
11) (a) 97,000,000 (b) 1.4x10 to the power of 8 (c) 1.08x10 to the power of 9 (d) K=11
12) (a) 5.2 (b) 5
13) (a) M=0.25xp to the power of 3 (b) 31.25
14) x+5/2x+1
15) (a) 8x-1/15 (b) 2a3e2 (c) y=4.8
16) (a) 6/20, 4/20, 9/19, 6/19, 4/19, 10/19, 5/19, 4/19, 10/19, 6/19, 3/19 (b) 3/95 (c) 9/38
17) (a) 3 (b) 7 (c) x+5/2 (d) 4 or 1 = x
18) (a) 15 (b) 0.48 =12/25 Frequency density = frequency / width of interval
19) -5+12 Square Root (18)
20) Pi(300+100Square Root 2) = A
21) (a) In order from left to right, then down: (Set Theory)
4, 4, 6,
. 5,
6, . 2,
. 3
(b) 9/64
22) (a) MN = 2q-4p (b) PR = 0.5p+q (c) QR = 0.5p, OP = p
_____________________________________________________


Wasn't Q1 3n+7 because the sequence was 7,10,13,16,19,21 etc?
Reply 6
Original post by Dr Carlsberg
Wasn't Q1 3n+7 because the sequence was 7,10,13,16,19,21 etc?


If it was 3n+7 the first number would be 3(1) + 7 = 10, with the second number being 3(2) + 7 = 13
Original post by James the 23rd
I think for part b of the Venn diagram question it was 5/9 and not 9/64, as it asked the probability of the students who both owned a desktop and a laptop to also have a tablet.


I agree.
Original post by MattB_
If it was 3n+7 the first number would be 3(1) + 7 = 10, with the second number being 3(2) + 7 = 13


OMG yeah, well that was stupid of me :unimpressed: Thanks for explaining though!
I think 13 a) was 4p^3 if memory serves correctly.
Reply 10
Original post by UmbralArbiter
I think 13 a) was 4p^3 if memory serves correctly.


I think it was 1/4 (0.25) as you had to cube whatever p was and then M (or whatever the other letter was!) was divided by that :smile:

Can anyone remember the question that was like (2x - 5)^2 as part of it... I think I messed it up!
Original post by fuzz13
I think it was 1/4 (0.25) as you had to cube whatever p was and then M (or whatever the other letter was!) was divided by that :smile:

Can anyone remember the question that was like (2x - 5)^2 as part of it... I think I messed it up!


Was that the difference of 2 squares one? (With x^2 -25 on the top)
Original post by fuzz13
I think it was 1/4 (0.25) as you had to cube whatever p was and then M (or whatever the other letter was!) was divided by that :smile:


Also, can you remember the 2 values stated for M and P?
that last functions question though wtff
With the Venn Diagram, the other result as well as (4, 4, 6, 2, 5, 6, 2, 3) was 2 on the outside so that the total was 32 students
Reply 15
For 21, most people I've spoken to got 5/9 as in 5 people in the middle out of 9 people with laptops, desktops and/or tablets? Anyone else get 5/9?
Original post by cringos
For 21, most people I've spoken to got 5/9 as in 5 people in the middle out of 9 people with laptops, desktops and/or tablets? Anyone else get 5/9?


Yes.
Doesn't Q 6 have a second part, where they ask about the original price during the sale?
Wasn't 16c 1/4?
Original post by zaggalicious
Doesn't Q 6 have a second part, where they ask about the original price during the sale?


Just times the stated value by 5 (or something similar)

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