Scroll to see replies
\displaystyle [br]\begin{equation*}r^2 -2\lambda r \cos (\theta - \alpha) + \lambda^2 = a^2 \end{equation*}
\displaystyle [br]\begin{equation*}r^2 -2\lambda r \cos (\theta - \alpha) + \lambda^2 = a^2 \end{equation*}
=\frac{a^2}{2}\displaystyle\int^{\frac{\pi}{2}}_0 sin(2\theta)} .d\theta
Last reply 3 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71
Last reply 3 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71