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RSS  Maths revision, coursework or discussion you will find help in here.
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Old 08-09-2005: 8th September 2005 16:40 #1 
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hi, im trying to do some maths homework set by my teacher, im stuck on a completly simple problem, that i cannot see the solution for, is there any chance anyone would walk me through how to do it, but without giving me the final answer, because i am at a loss of where to start, sorry x

heres the question anyway ("^" is to the power of and "/" is divide)

simplify this expression 21a^3 b^2 / 7ab^4

thanks, ash xx
 
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Old 08-09-2005: 8th September 2005 16:43 #2 
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the 21 and the 7 cancel out to leave three on the top (if u divide the top and bottom by 7), u can also divide the top and bottom by a, and by b^2.
u can do this because they are common in both the top and bottom of the expression
so the answer would be, i think, 3a^2/b^2
if this is not the answer in the back of the book im sorry, may have gone wrong somewhere
Old 08-09-2005: 8th September 2005 16:44 #3 
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ive just seen how iu can write it out better for you to understand, sorry guys (and girls) 21a³b²÷7ab4
 
Old 08-09-2005: 8th September 2005 16:47 #4 
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the answer in the back of the book is a²b-2a , like i said i bet you get allot of people coming here for quick answers but i care about my work and this has got me stumped, iv go to hav emy tea, but il be back in around 20mins, thanks again
 
Old 08-09-2005: 8th September 2005 16:55 #5 
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are u sure u are looking at the right answers? because there is no way u can get a²b-2a from 21a³b²÷7ab4 because there is no way u can get -2a as there are no +s or -s in the starting thing, what book are u using and what question and exercise in that book, as i have one infront of me, and would make more sense
Old 08-09-2005: 8th September 2005 17:00 #6 
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found your problem, u are doing edexcel core maths 1, and u are doing question 12 in exercise 1B, however u are looking at the answer in the back of the book to question 12 in exercise 1A
i was wrong too though to be honest, u do basically the same as i said before but the b's go to b^-2 as there is b^4 on the bottom and b^2 on the top and 2-4=-2
you probably know the answer really but were just confused about the answer given, i have done that so many times myself
Old 08-09-2005: 8th September 2005 17:00 #7 
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i apologise, the correct answer is 3a²b-2 which is the same as your answer, but written in a differnt way, sorry x the book im using is heinemann modular mathmatics for edexcel as and a level, core mathmatics 1, the question is exercise 1b, 12 sorry again
 
Old 08-09-2005: 8th September 2005 17:01 #8 
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beat me to it, yeah u were right, thsi is why i was confused, thanks anyway x
 
Old 08-09-2005: 8th September 2005 17:01 #9 
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seriously dont worry, i wasnt meant to sound mean before, i really wasnt, i was just confused myself
Old 08-09-2005: 8th September 2005 18:19 #10 
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right, im back, sorry for this, i m sooo out of touch, is this normal to struggle when u first start maths again after GCSEs, i seem to have forgoten so many simple things, and yet i got an A in the exams anyway, my question is this

if you had the sum whicn went along the lines of 3(x²)³
does that mean 3*x² all cubed or x², cubed * 3?
cheers
 
Old 08-09-2005: 8th September 2005 18:22 #11 
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Originally Posted by porter2002
right, im back, sorry for this, i m sooo out of touch, is this normal to struggle when u first start maths again after GCSEs, i seem to have forgoten so many simple things, and yet i got an A in the exams anyway, my question is this

if you had the sum whicn went along the lines of 3(x²)³
does that mean 3*x² all cubed or x², cubed * 3?
cheers
the second one, remember good old BIDMAS...
Old 08-09-2005: 8th September 2005 18:23 #12 
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thankyou ever sooo much
 
 
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