The limits were -1 , 1/4 and 3.
You had to split the graph into two, the negative area and the positive area
Using your integral, put in -1 and 1/4 for the negative area and it came out as 4. something?
then do the same for 1/4 and 3 for the positive area and it should come out as 36. something, add the 2 areas, so you get 40. something.
I used a graphical calculator to check :wink:

Reply 11

CitizensUnited

The method was to integrate the function, then put limits of 3 and -1 in. I think.

Reply 12

miajacks

Well you had to integrate the first bit , get the modulus of it and then add it to the integral of the bit on the right of the y axis. I must have made a slip somewhere.

Reply 13

AFK

I got 40.8 for the last question.

Had to added 36.4 to 4.4 or something.

Reply 14

AFK

Messed up the question involving the obtuse angle though. Gave it in degrees instead of radians

Reply 15

charlielower

i got 32 exactly, graphical calculator says so too..............did anyone get 2.44-2.55 radians for the obtuse angle question?

Reply 16

maymaymo

Original post by charlielower

i got 32 exactly, graphical calculator says so too..............did anyone get 2.44-2.55 radians for the obtuse angle question?

I got that originally, then realised that the graphical calculator minused the area under the x-axis, instead of adding it.

Reply 17

charlielower

oh daym, only dropped one mark for that then

Reply 18

shan735

I got 32 for the area of the integral

Find the area from -1 to a 1/4

then find the area from 1/4 to 3 :smile:

For the obtuse angle i also got 2.44 or something similar

Also for that 3Tan2x=1 question really scared me :L I panicked and used the 2tanA/1-tan^2A

In the end, i remembered, and I found out...IT BOTH WORKS :biggrin: