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Proving That (a+b)^n=?_(r=0)^n??(n¦r) a^(n-r) ? b^r
:smile:
Reply 1
Original post by Mhymie
Proving That (a+b)^n=?_(r=0)^n??(n¦r) a^(n-r) ? b^r
:smile:


(a+b)n=r=0n(nCr.a(nr).br)(a+b)^n= \sum_{r=0}^n(^nC_r . a^{(n-r)} . b^r)

Use Induction?
(edited 13 years ago)
Reply 2
yes..
I mean that..
but I can't set the formulation...
thanks...

U can help me..?
Reply 3
Original post by Mhymie
yes..
I mean that..
but I can't set the formulation...
thanks...

U can help me..?


As I said above, try using induction?

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