IF you would like help with any math problems, feel free to post them

For question 1, remember $cos(\theta) = cos(-\theta) \text{ and } sin(-\theta)=-sin(\theta)$

So $cos(k \theta)$ can be written as $cos(-k \theta)$ while $sin(-k \theta)$ can be written as $-sin(k \theta)$

could you explain how to do this for me please?!

(2+1)log base 4 3x + log base 4 3x =1

I make the 1 a log of log base 4 4 and then i know i'm meant to turn it into a quadratic but don't know how!

Was also wondering if you could explain Increasing and Decreasing function to me if possinble?
Ty

2.

$(\cos \theta + i\sin \theta)^p = \cos \theta p + i\sin \theta p$

I don't know why you didn't just write 3 instead of (2+1), but this is what I get, although I may well be wrong.

$3\log_4 3x + \log_4 3x = 1$

Then, $\log_4 9x^3 +\log_4 3x = 1$

I don't know why you didn't just write 3 instead of (2+1), but this is what I get, although I may well be wrong.

$3\log_4 3x + \log_4 3x = 1$

Then, $\log_4 9x^3 +\log_4 3x = 1$

Thus, $\log_4 27x^4 = 1$

So, $27x^4 = 4$

And finally, $x = \sqrt[4]{\frac{4}{27}}$

Just put that into the initial and didn't get one, so I am curious where I went wrong, any help ?

JuHahaha. Thx for the reply! Just realsied it should have been (2x +1) not 2 + 1 cringe....

You might have already got this far but I eventually get stuck at:

$(3x)^{x+1}= 2$

After this I don't think (to the best of my limited knowledge) you can use algebra to solve it.

IF you would like help with any math problems, feel free to post them

Is this a serious thread? Or a joke one lol?



If y = cost, and x = cos2t, then we can deduce dy/dx = =1/4cost. Find d^2y/dx^2.

Is this a serious thread? Or a joke one lol?



If y = cost, and x = cos2t, then we can deduce dy/dx = -1/4cost. Find d^2y/dx^2.

$\displaystyle \frac{dy}{dx} = \frac1{4cost}=\frac14sect$

Now just differentiate it again, remember, $\displaystyle \frac{d}{dx}(secx) = secxtanx$

Edit: Why is my latex smaller than everyone else's ?

Is this a serious thread? Or a joke one lol?



If y = cost, and x = cos2t, then we can deduce dy/dx = -1/4cost. Find d^2y/dx^2.

If you would like help with any maths problems, feel free to reply to this post