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The Edexcel C1 (16/05/12 - AM) Revision Thread

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Reply 180
Original post by Wooden
I believe Transformations of graphs is in C1..

..I can't get my head around it! Can someone explain quick short way to remember what happens

for e.g. y = f(x) + a ..soemthing happens to x or y axis by something blah blah..I can't remember this very good way to remember it.

cheers


F(x) + a = Move up A units

F(x) - a = Move down A units

F(x+a) = Move left A units

F(x-a) = Move right A units

-f(x) = Multiply y coordinates by -1

f(-x) = Multiply x coordinates by -1

af(x) = Multiply y coordinates by a

f(ax) = Multiply x coordinates by 1/a
Original post by Wooden
I believe Transformations of graphs is in C1..

..I can't get my head around it! Can someone explain quick short way to remember what happens

for e.g. y = f(x) + a ..soemthing happens to x or y axis by something blah blah..I can't remember this very good way to remember it.

cheers


y = f(x) + a it shifts to the left :smile:

...

just learn the rules carefully! :wink:
Original post by Wooden
I believe Transformations of graphs is in C1..

..I can't get my head around it! Can someone explain quick short way to remember what happens

for e.g. y = f(x) + a ..soemthing happens to x or y axis by something blah blah..I can't remember this very good way to remember it.

cheers


I remember it like this:
If it's inside the bracket, do the opposite to the x-co-ordinate. E.g. y = f(x-3) would add 3 to the x co-ordinates.
If it's outside the bracket, do what it says to the y-co-ordinate. E.g. y = f(x)+5 would add 5 to the y co-ordinates.
Reply 183
Original post by pbn
how would you work out the points for it though?
and I've just looked at the answers and they made dy/dx=0 then factorised by putting x as the origin 0, the used quadratic formula to get A and B, then did A-B to get AB; Is this what you meant and I'm just too slow to understand x_x hahah


I thought they had already given you the points. But if they haven't then you differentiate the equation, find out the gradient (by substituting an x-value they must have given you), find out the equation, and then by using the equation work out the coordinates.

So you are right :smile:
There's always a question on the

normal, tangent, gradient, use of y-y1 = m (x - x1 )

factorisation of a quadratic very common in the sequences series questions

examiners reports say alot of candidates make careless errors with negative numbers and indices

know your surd and indices rules! :smile: always a question on this
Reply 185
Original post by pbn
how would you work out the points for it though?
and I've just looked at the answers and they made dy/dx=0 then factorised by putting x as the origin 0, the used quadratic formula to get A and B, then did A-B to get AB; Is this what you meant and I'm just too slow to understand x_x hahah


When I did that question I factorised as well
From part A you have to integrate the f'(x) from that you should get

f(x) = 6x -2x^2 - x^3

A and B occur when f(x) is = 0 You have to remember that the points lie on the x axis so there y value must be 0

so you get the eqaution

6x -2x^2 - x^3 = 0

^ Take out the x then use completing the square or qaudratic formula

and you should get the answer
Reply 186
how do you work out the area of a triangle on a graph?
Reply 187
Btw when your asked to work out the area of a triangle and you don't have the perpindicular hieght what do you do?
Reply 188
Original post by rosie66
how do you work out the area of a triangle on a graph?


Same way you would work out the are of a normal triangle, but instead of the length being in centimetres, it is going to be in coordinates now.
Reply 189
Original post by 0range
When I did that question I factorised as well
From part A you have to integrate the f'(x) from that you should get

f(x) = 6x -2x^2 - x^3

A and B occur when f(x) is = 0 You have to remember that the points lie on the x axis so there y value must be 0

so you get the eqaution

6x -2x^2 - x^3 = 0

^ Take out the x then use completing the square or qaudratic formula

and you should get the answer


Thank you! :smile: have you done a lot of the solomon papers?
Original post by 0range
Btw when your asked to work out the area of a triangle and you don't have the perpindicular hieght what do you do?


You can work out the perpendicular height :smile: I will post an example in a second :smile:
Reply 191
Original post by usycool1
You can work out the perpendicular height :smile: I will post an example in a second :smile:


thank you :smile:
Reply 192
Has anyone got a quick list of the most important formulae were supposed to remember?
Original post by pbn
Has anyone got a quick list of the most important formulae were supposed to remember?


x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}

b24acb^2-4ac

And they give us the arithmetic progression formulas :smile:
Reply 194
Original post by pbn
Has anyone got a quick list of the most important formulae were supposed to remember?


Found this very useful; C1 in a page.
(edited 11 years ago)
Reply 195
Original post by usycool1
x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}

b24acb^2-4ac

And they give us the arithmetic progression formulas :smile:


Thank you :smile: , after i posted this I realised most of the harder formulae are for C2 anyhow and I already have it thankfully.
Reply 196
Original post by vxrz
Found this very useful; C1 in a page.


Thank you! Have you got this for any other maths units like C2 or S1? :smile:
Reply 197
does any one have an example of how to find the perpendicular height?
Reply 198
Original post by intellectual1
There's always a question on the

normal, tangent, gradient, use of y-y1 = m (x - x1 )

factorisation of a quadratic very common in the sequences series questions

examiners reports say alot of candidates make careless errors with negative numbers and indices

know your surd and indices rules! :smile: always a question on this


whats the tangent of the normal? does that imply perpendicular?
Original post by intellectual1
y = f(x) + a it shifts to the left :smile:

...

just learn the rules carefully! :wink:


I think you should go back and look at the rules again...

f(x) + a moves up in the y axis ...

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