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CHEM1 15 May 2012 AQA OFFICIAL POST EXAM

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Original post by Crescentise
I agree with this. There were loads of large nested calculation questions where you had to think of a route to the end, whereas in pretty much every single paper in the past, it was just one question made up of 1-mark a), b), c) and so on.



I drew the alkene as a cyclic alkane. Cyclobutane, I think it was.


aah of course thanks
Original post by Crescentise

I drew the alkene as a cyclic alkane. Cyclobutane, I think it was.


I did this too. I just drew a square though (and didn't write in the carbons) but drew 2 hydrogens coming off each corner, think they'll accept that?
Reply 42
what was the answer to the 5 marker on the second last page? the concentration in moldm3 one?
Original post by joker12345
I did this too. I just drew a square though (and didn't write in the carbons) but drew 2 hydrogens coming off each corner, think they'll accept that?


You'd like to think so seeing as they represent cycloalkanes like that in exams .. and it is correct!
Original post by joker12345
I did this too. I just drew a square though (and didn't write in the carbons) but drew 2 hydrogens coming off each corner, think they'll accept that?


i think they wanted a full displayed formula, it was one mark so i doubt they'd be flexible
Original post by CelineG
what was the answer to the 5 marker on the second last page? the concentration in moldm3 one?


I second this .. what were people getting?
Original post by travispickle
I did: (85x2.5) + (87x1)
divided all that by 3.5

Got 85 something, I think..
It felt right..


I did the exact same thing; got 85.4.
Original post by EllaBella<3
I second this .. what were people getting?


lots of people got around 2
85.6****
Original post by EllaBella<3
I second this .. what were people getting?


2. something ... a pretty big value for a concentration :/
Reply 50
Original post by Ahmad*
I did the exact same thing; got 85.4.


I think they will allow any multiple of 2.5 and 1 really because you get the same answer for each multiple..
Original post by joker12345
2. something ... a pretty big value for a concentration :/


oh my bad i think that was the mass Q
Original post by joker12345
2. something ... a pretty big value for a concentration :/


That's exactly what I thought :s-smilie: but I got it too. Quite a lot of people seem to have got that.
Original post by joker12345
2. something ... a pretty big value for a concentration :/


Ahhh, I wrote something like 2.02 then had a last minute panic in my checks and crossed it out .. grrrrrrr. Hopefully I should get a few method marks though :s-smilie:
Reply 54
Original post by travispickle
I did: (85x2.5) + (87x1)
divided all that by 3.5

Got 85 something, I think..
It felt right..


I did the sane thing :smile:
People that used 20 and 50 as the abundances would need to divide by 70 as you always divide by the sum of the abundances.
Original post by Ahmad*
I did the exact same thing; got 85.4.


but there was more of the 87 isotope, therefore the number has to be close to 87
so probably around 86.4
Reply 56
Wasn't the molecular formula ratio 1:2? so it was BCl2???
Reply 57
what did u guys get for atom economy question??
Reply 58
and PH3 what that trignol planner??
Original post by Crescentise
That's exactly what I thought :s-smilie: but I got it too. Quite a lot of people seem to have got that.


i can't remember what i put, but i'm pretty sure it's 0.7.... something

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