AQA Unit 3 Mathematics 13 June 2012 - Unofficial Mark Scheme [43603H] [GCSE]

Mark Scheme in Word Format - very thorough, many thanks to Empty Child for posting this! (Click below link)
http://www.thestudentroom.co.uk/attachment.php?attachmentid=156920&d=1339627392

Click Spoiler for Original Unofficial Mark Scheme (unfinished)

Spoiler

For everyone inquiring about Grade Boundaries; as this is the first time this paper has been sat, there is no previous grade boundaries to give a rough indication.

It has been suggested, with the paper being out of 80 marks that the following grade boundaries may suit:
66 - A*
52 - A
41 - B
33 - C

**Please don't assume these are correct, they are just rough ideas posted on TSR

(edited 11 years ago)

Reply 1

taz180496

no one post any answers as this will give foreigners 12hours behind us the advantage which will in return result the increase of the boundaries.

Reply 2

AP1994

yes please dont post anything and take that question with the answer?
dont wanna fail

Reply 3

PrinceUpsb

OP

14

Original post by AP1994

yes please dont post anything and take that question with the answer?
dont wanna fail

Original post by taz180496

no one post any answers as this will give foreigners 12hours behind us the advantage which will in return result the increase of the boundaries.

This is AQA. Those rules only apply to Edexcel exams.

Reply 4

07khan_A

can u please post some more answers thanks

Reply 5

07khan_A

Original post by PrinceUpsb

//Under Construction
//Under Construction

Question 10: (Concert - standing area - amount of people)
(15*10)-((Pi*3^2)/2)= 135.862...

135.862.../0.3 = 452.876...

Answer = 452 as you cannot have 0.876 of a person and 453 people would require more space
----
Question ?: (Find t - triangle - parallel lines)

Angle opposite w+40 must also be w+40.
Angles within parallel lines add to 180.
This means you had four angles around the point that were as follows: w+40, 108, w+40, 108.
Work out w: 2w+80=(360-108-108)=144
2w=64
w=32

t=180-(w+40)-(2*w)=44
---

hi i took this paper today and got the same answer :smile:

what did you get for the question with the quadrilateral made of 2 triangles - you had to calculate the area ??? thanks

Reply 6

Maths94

4

For question 15 where it was something like 3x+x2-10=0
What answers did use get and did you use trial and improvement?

Reply 7

xxDanxx

For Q10, the answer 135.... I think the paper said it had to be squared then / 0.3

Maximum number = area of standing area(squared) / 0.3

Giving an answer of around 61,528.27 (61,528 rounded)

Reply 8

xxDanxx

Original post by Maths94

For question 15 where it was something like 3x+x2-10=0
What answers did use get and did you use trial and improvement?

That wasn't the question it was

3x(Squared) + 4x - 10

You had to factorise by using the quadratic equation. Obtaining 2 different x values.

(edited 11 years ago)

Reply 9

Maths94

4

Yeah that question. What was your final answer ?
I don't know why i got x = 0.90 ( guess really lol )
On the question where there is 2 parts (a) (b) you had to find R through M or something what did you get for them two ?

Reply 10

PrinceUpsb

OP

14

Original post by xxDanxx

For Q10, the answer 135.... I think the paper said it had to be squared then / 0.3

Maximum number = area of standing area(squared) / 0.3

Giving an answer of around 61,528.27 (61,528 rounded)

I don't believe it did

Reply 11

xxDanxx

Can't remember my answer for R and M question but for my x values I think I had 1.27 and -2.6

OP:

Q:1

It was a straight line with 3 different angles upon it. 2x, 3x and 4x. You have to calculate smallest angle.

ANSWER:

2x + 3x + 4x = 180 Degrees
9x = 180 Degrees
x = 180 / 9
x = 20
2x = 20 * 2 = 40 Degrees

Reply 12

Maths94

4

Yeah for question 1 i got 40 Degrees

Reply 13

xxDanxx

There was a rotational question. Rotate a shape 90 degrees clockwise around point (0,1)

CBA drawing graph but that was question

Reply 14

Antheran

7

Original post by xxDanxx

For Q10, the answer 135.... I think the paper said it had to be squared then / 0.3

Maximum number = area of standing area(squared) / 0.3

Giving an answer of around 61,528.27 (61,528 rounded)

I was about to make the same mistake as you but then I realised that the area of the place is already in metres squared so squaring it again kind of suggests that you're not entirely sure what you're doing and is obviously wrong.

Reply 15

dc747

Am I the only one who thinks the question with the triangles cut from the square was very misleading? The diagram (though not drawn accurately I acknowledge) seemed to imply the sides of the triangle were not the same as the base, yet the question said they were. The discrepency between the diagram and the question was huge, so I worked out what the sides of the triangle were and used that for perimeter. In hindsight I guess I should have ignored the diagram :frown:

Reply 16

Vernish

4

Original post by dc747

Am I the only one who thinks the question with the triangles cut from the square was very misleading? The diagram (though not drawn accurately I acknowledge) seemed to imply the sides of the triangle were not the same as the base, yet the question said they were. The discrepency between the diagram and the question was huge, so I worked out what the sides of the triangle were and used that for perimeter. In hindsight I guess I should have ignored the diagram :frown:

Did that too. :frown:

Reply 17

JamesWire

They were, but as they were slanted they did not reach the top of the square.

Reply 18

AdamskiUK

13

Original post by dc747

Am I the only one who thinks the question with the triangles cut from the square was very misleading? The diagram (though not drawn accurately I acknowledge) seemed to imply the sides of the triangle were not the same as the base, yet the question said they were. The discrepency between the diagram and the question was huge, so I worked out what the sides of the triangle were and used that for perimeter. In hindsight I guess I should have ignored the diagram :frown:

I considered doing that, but it did say not drawn accurately (I think). I was tempted though.