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Prove there exists no polynomial f(x) f(x) with integer coefficients such that f(a)=b, f(b)=c, f(c)=a f(a)=b, \ f(b)=c, \ f(c)=a for a,b,c a, b, c distinct integers.
Reply 1781
Original post by DJMayes
Well, all I can say is I'm glad you're not applying to the same college at Cambridge as I am :tongue:

Half of my competition at St John's probably come from about three public schools so I'm not sure about applying to my college either. :rolleyes:
Original post by und
Half of my competition at St John's probably come from about three public schools so I'm not sure about applying to my college either. :rolleyes:


You're not going to be in the TSR Pembroke Maths war though :wink:
Reply 1783
Original post by DJMayes
You're not going to be in the TSR Pembroke Maths war though :wink:

I'm guessing you find yourself embroiled in that then. I have a feeling that the Pembroke admissions tutors are going to be pleasantly surprised this year.
Reply 1784
Original post by und
I'm guessing you find yourself embroiled in that then. I have a feeling that the Pembroke admissions tutors are going to be pleasantly surprised this year.


Before they start stalking us on TSR
Reply 1785
Original post by Cephalus
For functions like 1/(1+x), the maclaurin expansion is the same as its binomial expansion, which is what I think they are expecting


Ah, I was thinking binomial but it didn't quite work. I'll take another look tomorrow when my eyes can focus again :tongue:
Original post by und
I'm guessing you find yourself embroiled in that then. I have a feeling that the Pembroke admissions tutors are going to be pleasantly surprised this year.


Yeah, I've applied there. It will be interesting to see how that plays itself out :tongue:
Original post by L'art pour l'art
Prove there exists no polynomial f(x) f(x) with integer coefficients such that f(a)=b, f(b)=c, f(c)=a f(a)=b, \ f(b)=c, \ f(c)=a for a,b,c a, b, c distinct integers.


Is it NOT from Putnam or IMO or something similar in difficulty? Just deciding if I should try it. :biggrin:
Original post by Dog4444
Is it NOT from Putnam or IMO or something similar in difficulty? Just deciding if I should try it. :biggrin:
Got it from someone who said it's from a book on the theory of functions. Give it ago. :wink:
Original post by Lord of the Flies
If you want weird take a look at xxxx^{x^{x^{\cdots}}}


Determine the interval of convergence for x^{ \infty} x

Spoiler

Original post by TheMagicMan
Determine the interval of convergence for x^{ \infty} x

Spoiler



Easy to show that the upper bound is e1ee^{\frac{1}{e}}, but I am encountering a problem with oscillations for small x, which I am assuming is the difficulty in the problem - the issue can probably solved by separating cases of odd and even tetration, but given that it's 6:30 am I need to get some sleep first.

(I think we had only resolved part of the problem on the other thread - the easy part) :rolleyes:
Pretty pleased with myself today, I managed 1,2,3 and 5 in an hour before I went to sleep last night of the 2006 STEP I paper.. Bit annoying as I've taken quite a break from practise :lol:

Also, I attempted to differentiate xxxx^{x^{x}} and was wondering if anyone could confirm my answer.

Spoiler



and my attempt at xxxxx^{x^{x^{x}}}

Spoiler


(edited 11 years ago)
Reply 1792
Original post by Oromis263
Pretty pleased with myself today, I managed 1,2,3 and 5 in an hour before I went to sleep last night of the 2006 STEP I paper.. Bit annoying as I've taken quite a break from practise :lol:

Also, I attempted to differentiate xxxx^{x^{x}} and was wondering if anyone could confirm my answer.

Spoiler



and my attempt at xxxxx^{x^{x^{x}}}

Spoiler



Stick it into Wolfram if you want to be sure but from a quick glance it looks much the same as my answer. It's easy to see what the pattern is in general.
Reply 1793
Original post by Oromis263
Pretty pleased with myself today, I managed 1,2,3 and 5 in an hour before I went to sleep last night of the 2006 STEP I paper.. Bit annoying as I've taken quite a break from practise :lol:

Also, I attempted to differentiate xxxx^{x^{x}} and was wondering if anyone could confirm my answer.

Spoiler



and my attempt at xxxxx^{x^{x^{x}}}

Spoiler




Yes, they're right.

Extension: Prove by induction a general formula for ddxnx\frac{\mathrm{d} }{\mathrm{d} x} ^{n}x.
Reply 1794
I think we should have some easier interview style questions in this thread, like:

Find 11x2\int^{1}_{-1} x^{-2}
Original post by Zuzuzu
Yes, they're right.

Extension: Prove by induction a general formula for ddxnx\frac{\mathrm{d} }{\mathrm{d} x} ^{n}x.


Will try it now. :smile:

Original post by und
I think we should have some easier interview style questions in this thread, like:

Find 11x2\int^{1}_{-1} x^{-2}


It doesn't converge? :s-smilie: Although I did notice it was even, and changed the limits in the hope it might help, sadly it didn't.
[QUOTE="Oromis263;40175826"]
It doesn't converge? :s-smilie: Although I did notice it was even, and changed the limits in the hope it might help, sadly it didn't.
Sketching the graph reveals all... I think it's almost always worth doing that in integration (unless the function would take a while to sketch).

A similar example may include:

03(1x)2\displaystyle \int^{3}_{0} (1-x)^{-2}
(edited 11 years ago)
Original post by und
I think we should have some easier interview style questions in this thread, like:

Find 11x2\int^{1}_{-1} x^{-2}


Is this a trick question?

Or is it really 2 :s-smilie:

:reel:
Reply 1798
Original post by Oromis263
Will try it now. :smile:



It doesn't converge? :s-smilie: Although I did notice it was even, and changed the limits in the hope it might help, sadly it didn't.


Original post by L'Evil Fish
Is this a trick question?

Or is it really 2 :s-smilie:

:reel:


It's a real interview question. :wink:

Not for Cambridge through. Not for Mathematics either.
(edited 11 years ago)
Original post by und
It's a real interview question. :wink:

Not for Cambridge through. Not for Mathematics either.


So is the answer 2?

:reel:

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