AQA Physics A Unit 4- 11 June 2014

naa my school only teach medical because its supposedly the easiest, i irk it. im a maths guy haha doing maths at uni. its just medical for the optional on unit 5. good luck with everything, im guessing hca work is something related to medicine ~

Could someone who knows where it is link it, I don't want to have to look through 19 pages

''claree'' did a few days ago search and you'll find it

I couldn't find it - I did find a list of questions but not six-markers

I couldn't find it - I did find a list of questions but not six-markers

its maybe on page 3 or 4

naa my school only teach medical because its supposedly the easiest, i irk it. im a maths guy haha doing maths at uni. its just medical for the optional on unit 5. good luck with everything, im guessing hca work is something related to medicine ~

Could someone please explain this question? I can never get these ones correct!


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Is the answer C. You would have to rotate the whole thing across the field to make sure it cuts the field lines, as it would then change the magnetic flux linkage, hence creating an induced current and producing an induced emf.


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Thank you!! So the field lines aren't cut the other ways?

I'm probably just losing the plot here and missing the painfully obvious, but how would you do these?

(Ignore the working and sorry the second is lopsided haha)


Posted from TSR Mobile

Thank you!! So the field lines aren't cut the other ways?

I'm probably just losing the plot here and missing the painfully obvious, but how would you do these?

(Ignore the working and sorry the second is lopsided haha)


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Well for the second one, you know that V is proportional to (-)1/r, so you can see that V for the 4kg one will be 6J as r * 2---> v/2. Now just sub into W=M* delta v , where deta v is 6-3=3 and 4*3=12J


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does anyone know of any exam solutions type websites for physics? using the mark scheme when I don't understand a question really doesn't help!

Stop it everyone. This is the mark scheme!

Q13. Near the surface of a planet the gravitational field strength is uniform and for two points, 10 m apart vertically, the gravitational potential difference is 3 J kg–1. How much work must be done in raising a mass of 4 kg vertically through 5 m?
A3 J
B6 J
C 12 J
D15 J
Points 5 metres apart will have gravitational potential difference of 1.5 J kg–1.
4 kg are lifted so 6J work is done.

Thank you!! So the field lines aren't cut the other ways?

I'm probably just losing the plot here and missing the painfully obvious, but how would you do these?

(Ignore the working and sorry the second is lopsided haha)


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