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The Official Edexcel FP2 Thread 6th June 2014

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Reply 20

Nough

Just looking at that pink image, I did so badly..
60/75?

Reply 21

clewis09

I did the right method for 4(a) but got the wrong coefficients. I also didn't have time to do 4(b) but wrote that u+iv= proved fraction, which seems like the kind of dumb thing edexcel give a mark to.

Any idea how many marks I dropped?

Also any idea what the grade boundaries will be like this year?

Reply 22

milworthy

Original post by BringerOfPie

4b is pi/18, pi/9, 7pi/18

not 5pi/18

pretty sure anyway

5a y = e^-3x (etc) looks like a copy error on your part

Was 7b finding f(x) as y^-3 = ... or as y = ... ?

6b was hard

edit: sorry for double post, pls dont kill

I think it was 5pi/18

Reply 23

BringerOfPie

Original post by milworthy

I think it was 5pi/18

ah bugger me you're right, i got it confused with a sin graph for that answer. just ran through it again and got 5pi/18.

*commits sokoban*

Reply 24

Dorrez2k12

For the complex number one, how did you do part b? I got the real and imaginary parts of w from part a and 'forged them' to be (u-3)^2 and v^2. All the x's cancelled. Does that count as showing the answer if I got the right value of k?

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Reply 25

1298977

Anyone remember question 6B?

Reply 26

forsparta

65/75 **** complex numbers man

Reply 27

Dorrez2k12

ImageUploadedByStudent Room1402069268.597028.jpg

Does this count as a solution to 6b considering it said show that?

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Reply 28

Agecaf

For the complex number one, as it was a "show that", I don't think there is another sensible way of finding the solution other than just finding u, v and "showing that" (u-3)^2 + v^2 = 25.

Reply 29

HateFP2

Any ideas on how much lower the grade boundary will be compared to previous years?

Reply 30

Dorrez2k12

I realise there is. If you re-arrange x into terms of u, and sub that into v, it does cancel. But it isn't nice, and certainly isn't 4 marks....
Not sure how they wanted you to do it :frown:

What's the worst case in doing it my way?

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Reply 31

derekluong

Original post by Dorrez2k12

Does this count as a solution to 6b considering it said show that?

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Thats right, but how did u show that x cancelled out?

Reply 32

Dorrez2k12

Original post by derekluong

Thats right, but how did u show that x cancelled out?

I went through all the algebra, got pretty nasty...

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Reply 33

BringerOfPie

Original post by Dorrez2k12

I realise there is. If you re-arrange x into terms of u, and sub that into v, it does cancel. But it isn't nice, and certainly isn't 4 marks....
Not sure how they wanted you to do it :frown:

What's the worst case in doing it my way?

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given you used the target of the show that in your working, you'll probably lose the method marks

but its only 4 marks so its probably M2A2 (worst case M3A1 as it gives you the answer)

Reply 34

Dorrez2k12

Original post by BringerOfPie

given you used the target of the show that in your working, you'll probably lose the method marks

but its only 4 marks so its probably M2A2 (worst case M3A1 as it gives you the answer)

Okay thanks for your opinion.
In doing it the second way I suggested took a lot of work. Ijust tried it, didn't seen like 4 marks

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