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This question is about the vibrational testing of a satellite.
The vibrations simulate the shaking the satellite would undergo during launch. Assume the vibrations are simple harmonic

When oscillating the velocity of the satellite is given by the equation

Velocity = 2pifAcos(2pift)

Where f = frequency
A = amplitude
t = time

Explain how the equation shows that the maximum velocity of the satellite is given by

Maximum velocity = 2 pi f A ?

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Reply 21

PP0121

If Im asked to calculate the maximum velocity of the satellite now knowing that when it oscillates he frequency is 11Hz with an amplitude of oscillation of 42mm

Is the maximum velocity 2 x pi x 11 x 42^2??

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Reply 22

Alex621

for the first part I would assume it is because the maximum possible value of cos(2pift) is always going to be 1

for the second part, it's 2 x pi x 11 x 42x10^-3, as the amplitude must be in metres

Reply 23

PP0121

Thanks

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Reply 24

PP0121

How did you find the mark scheme so quickly?

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Reply 25

Alex621

Original post by PP0121

How did you find the mark scheme so quickly?

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I copied and pasted the question into google, and it turns out the question was from a past paper :smile:

Reply 26

PP0121

Oh ok

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Reply 27

PP0121

I'm having problems with some chemistry transition work

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Reply 28

PP0121

I basically hardly understand any of it

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Reply 29

Alex621

oh sorry I don't do chemistry, maybe make a thread in the chemistry section

Reply 30

PP0121

I've made two but I don't think anybody's really willing to help me or at least I am not getting replies for them . It's jut this whole homework that I don't get

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