JavaScript help please?

Original post by Dancatpro

I'll get you started with some pseudocode.

If x/3 is an integer and x/5 is an integer then return ???? (I know there is another word you have missed for this game)

ElseIf X/3 is an integer then return flip

ElseIf X/5 is an integer then return blop

Else Return X

End If

________________

I'm not on TSR much so you will have to get someone else to answer questions

You have misunderstood the question.

Reply 2

Original post by bobbyideye

How would you code the following:
"Flip" returns for every number where a 3 appears (ie 3,13,23 etc) would return Flip
"Blop" returns for every number where a 5 appears ie (5,15,25,35..)

the rest return as their ordinary self.
?
ie)
1,2,flip,4,blop,6,7,8,9,10,11,12,flip etc

What happens when a number contains both a 3 and a 5?

Cycle through the digits using the remainder operator (%10), checking if they are 3 or 5.

Reply 3

Put the lot in as strings in an array; check each element using an if block which uses the charAt() method to check for '3' and '5' and replaces the string appropriately, with this block nested in a for loop which iterates over each character in the string, which itself is nested in a for loop which iterates over each string in the array.

Done. Quite a simple algorithm.

P.S using numerical methods is an utter waste of time. You have already said that you are working with strings, and so you should look at string-based solutions to your problem.

(edited 8 years ago)

Reply 4

Joel_tsr

1

You could try using x%10==3 and x%10==5 to take care of the units column. To check the 10s column, you could try if (math.floor(x/10))%10==3 and similarly for 5. (I think this works. Haven't done any JavaScript in a while). The same method should work for 100s columns and above.

Posted from TSR Mobile

Reply 5

Original post by Joel_tsr

You could try using 1)x%10==3 and 2)x%10==5 to take care of the units column. To check the 10s column, you could try if (math.floor(x/10))%10==3 and similarly for 5. (I think this works. Haven't done any JavaScript in a while). The same method should work for 100s columns and above.

Posted from TSR Mobile

1) Solutions are x = 13 + 10n, where n is a positive integer.
2) Solutions are x = 15 + 10n, where n is a positive integer.

The meaning of this is that there is no single-digit solution to either of these equations - they cannot possibly provide the correct solutions of 3 and 5 respectively.

Reply 6

MrDare360

For anyone thinking this is a FizzBuzz problem it isn't.

Just convert the int to a string and check if the string contains a 3 or a 5 and then change the string to something else, then you loop through all your strings and print them out.

Reply 7

Original post by VannR

1) Solutions are x = 13 + 10n, where n is a positive integer.
2) Solutions are x = 15 + 10n, where n is a positive integer.

The meaning of this is that there is no single-digit solution to either of these equations - they cannot possibly provide the correct solutions of 3 and 5 respectively.

You're wrong.

Reply 8

Original post by Jooooshy

You're wrong.

Nah.

Reply 9

Original post by VannR

Nah.

3%10 = 3

Reply 10

Original post by Jooooshy

3%10 = 3

The % (modulus) operator returns the integer remainder produced in the calculation LHS / RHS. Therefore, 3%10 = 0 since 3/10 is less than 1 and the integer value would probably be truncated to 0 in a program. Even if you were to write this as 10%3, you would receive a value of 1 since 3 goes into 10 3 times, leaving an integer remainder of 1.

Reply 11