SHM
www.ocr.org.uk/Images/60451-question-paper-unit-g484-the-newtonian-world.pdf
the velocity of the mass is proportional to displacement- why is this false if v=2pi*f*A?
the velocity of the mass is proportional to displacement- why is this false if v=2pi*f*A?
a is proportional to displacement by definition of SHM
so a = kx (k is actually -omega2)
rewritten as v/t = -omega2 * x
rewritten as v = -omega2 * x * t
For v to be proportional to x, -omega2 * t would have to be a constant. Clearly this is not the case because t varies.
It cannot be proportional to displacement.
Btw that equation in your original post can only be applied where the amplitude = x, - before then you must use v = -A * 2pi * f * sin (2pi * f * t)
so a = kx (k is actually -omega2)
rewritten as v/t = -omega2 * x
rewritten as v = -omega2 * x * t
For v to be proportional to x, -omega2 * t would have to be a constant. Clearly this is not the case because t varies.
It cannot be proportional to displacement.
Btw that equation in your original post can only be applied where the amplitude = x, - before then you must use v = -A * 2pi * f * sin (2pi * f * t)
Original post by Student403
a is proportional to displacement by definition of SHM
so a = kx (k is actually -omega2)
rewritten as v/t = -omega2 * x
rewritten as v = -omega2 * x * t
For v to be proportional to x, -omega2 * t would have to be a constant. Clearly this is not the case because t varies.
It cannot be proportional to displacement.
Btw that equation in your original post can only be applied where the amplitude = x, - before then you must use v = -A * 2pi * f * sin (2pi * f * t)
so a = kx (k is actually -omega2)
rewritten as v/t = -omega2 * x
rewritten as v = -omega2 * x * t
For v to be proportional to x, -omega2 * t would have to be a constant. Clearly this is not the case because t varies.
It cannot be proportional to displacement.
Btw that equation in your original post can only be applied where the amplitude = x, - before then you must use v = -A * 2pi * f * sin (2pi * f * t)
thanks
Original post by runny4
thanks
No problem
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