yield 60.3%, Mr 119 or something like that, mass of carbon 0.173?, the peak at 0.00 was Si(ch3)4 and is a reference peak as it one intense peak as they are in the same environment, the rate equatation 0.244 and 0.120, k was 3.04 mol -2 dm 6 s-1, Ea=+47.4 kjmol-1.

Reply 27

bl0ndegiraffe

10

Original post by Sum Mmed

will i lose all 4 marks if i didnt convert volume to m3? i converted kpa to pa and celsius to K but did cm3 to dm3 and not m3!

if you did everything else right you might get 2 marks error carried forward?

Reply 28

mildhan

15

Original post by Photsonex

That's 5 though, was it 4 AND one with a fruity smell? I read it as 4 compounds, one of which had a fruity smell?

No that's only 4 compounds. There were two with a fruity smell, ethyl ethanoate and the ester with flavan-3-ol

Reply 29

Sum Mmed

9

oh ok thanks just checked old past paper mark scheme they cut 1 mark for each wrong conversion.

Original post by bl0ndegiraffe

if you did everything else right you might get 2 marks error carried forward?

Reply 30

slily

7

volume of propane was 9.6 dm3.

Reply 31

Beamomom

12

118 for MR
27.3 dm^3 volume
60.3% for yield
1.7g for mass
47.5kJ for activation energy

Reply 32

tesconyc

18

Original post by za1341

it was the ideal gas equation question

My bad i did OCR. That was close

Reply 33

slily

7

got the same except the volume as 9.6 dm3 and 0.173g for mass.

(Original post by Beamomom)118 for MR
27.3 dm^3 volume
60.3% for yield
1.7g for mass
47.5kJ for activation energy

Original post by Beamomom

118 for MR
27.3 dm^3 volume
60.3% for yield
1.7g for mass
47.5kJ for activation energy

Reply 34

Beamomom

12

Think I got those values for the rate equation, and k value was the same with units

Original post by slily

yield 60.3%, Mr 119 or something like that, mass of carbon 0.173?, the peak at 0.00 was Si(ch3)4 and is a reference peak as it one intense peak as they are in the same environment, the rate equatation 0.244 and 0.120, k was 3.04 mol -2 dm 6 s-1, Ea=+47.4 kjmol-1.

Reply 35

Beamomom

12

I don’t remember my mass for carbon tbh. I did 120/168 or whatever * 2 whatever

Original post by slily

got the same except the volume as 9.6 dm3 and 0.173g for mass.

(Original post by Beamomom)118 for MR
27.3 dm^3 volume
60.3% for yield
1.7g for mass
47.5kJ for activation energy