Edexcel A Level Chemistry 2019 Paper 2 June 11th 2019 Unofficial Mark Scheme

Original post by Munrhe

Anyone any idea about the flavanol structure of the Ester that we were meant to draw?

The poropanal in the question oxidised to carbonxylic acid. Carbonxylic acid will produce ester with alcohol, Flavanol, there are 4 structure of alcohol which are 4 optical isomer made from 2 chiral carbon that we found at the beginning

Reply 45

Pinkyprincess11

11

How did people find it ...I felt like it was quite different to previous past papers. I am actually pissed there didn’t put any organic synthetics question. Like I spent ages revising those😭!

Reply 46

WASSSJA

Original post by Beamomom

14.7/0.31 = 47.419–> which is the required mass of propane if you have a 31% yield and make 14.7g of the other thing. From there just calculate moles of propane then multiply by 24. Can someone explain what is wrong with this ?

yeh i did that

Reply 47

Original post by Beamomom

14.7/0.31 = 47.419–> which is the required mass of propane if you have a 31% yield and make 14.7g of the other thing. From there just calculate moles of propane then multiply by 24. Can someone explain what is wrong with this ?

The 47 one, because the mass required is the mass that should be produced, which is the expected mass

Reply 48

Hussain237363

For the activation energy I got 58kj? Would this still be fine ?

Original post by slily

got the same except the volume as 9.6 dm3 and 0.173g for mass.

(Original post by Beamomom)118 for MR
27.3 dm^3 volume
60.3% for yield
1.7g for mass
47.5kJ for activation energy

Reply 49

monisha e

7

What did you guys write for the recystalization and palladium catalyst question?

Reply 50

Beamomom

12

If that’s what you got from your graph, you should get that mark I think.

Original post by Hussain237363

For the activation energy I got 58kj? Would this still be fine ?

Reply 51

Dyzzle

9

Original post by slily

got the same except the volume as 9.6 dm3 and 0.173g for mass.

(Original post by Beamomom)118 for MR
27.3 dm^3 volume
60.3% for yield
1.7g for mass
47.5kJ for activation energy

Yeah I got the 27.9 dm^3 or whatever but that’s calculated with the Mr of propane not bromopropane

Reply 52

Hussain237363

DId u get any anomaly’s in the graph?

Original post by Beamomom

If that’s what you got from your graph, you should get that mark I think.

Reply 53

WASSSJA

?was it ethyl flavonate or the other way round for the ester or flavyl ethanoate

Reply 54

Original post by Beamomom

If that’s what you got from your graph, you should get that mark I think.

I think it needs to be in a range from 47-49kjmol-1

Reply 55

Dyzzle

9

So it’s wrong
It’s actually 9.6

Original post by Beamomom

14.7/0.31 = 47.419–> which is the required mass of propane if you have a 31% yield and make 14.7g of the other thing. From there just calculate moles of propane then multiply by 24. Can someone explain what is wrong with this ?

Original post by Beamomom

14.7/0.31 = 47.419–> which is the required mass of propane if you have a 31% yield and make 14.7g of the other thing. From there just calculate moles of propane then multiply by 24. Can someone explain what is wrong with this ?

It’s not the Mr of propane it’s the Mr of Bromopropane which is much higher, I made the same mistake

Reply 56

Dyzzle

9

Original post by monisha e

What did you guys write for the recystalization and palladium catalyst question?

I said (and I think it might be wrong) that palladium acts as a catalyst in a similar way to platinum in a catalytic converter so it forms O2 and N2

Reply 57

Hussain237363

In here I spoke about the adsorption and desorption theory

Original post by Dyzzle

I said (and I think it might be wrong) that palladium acts as a catalyst in a similar way to platinum in a catalytic converter so it forms O2 and N2

Reply 58