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Hi, in the question below in the mark scheme it converts 1/2root2 into 2^-3/4, is there a way to work this out?
(edited 1 year ago)
Original post by Username123455
Hi, in the question below in the mark scheme it converts 1/2root2 into 2^-3/4, is there a way to work this out?

It converts 1/2root2 into 2^-3/2 using normal indice arithmetic
1/2root2 = 1 / 2^(3/2) = 2^(-3/2)
Reply 2
Yes, so basically the 2√ 2 can be split in to: 2 times 2 which in other words is times 2^1/2. Now using the power rule, we know that we need to add the indices together so 1 + 1/2 is 3/2. Now we have 1 over 2^3/2 which can be rewritten as 2^-3/2. Hope this helps.
(edited 1 year ago)
Original post by mqb2766
It converts 1/2root2 into 2^-3/2 using normal indice arithmetic
1/2root2 = 1 / 2^(3/2) = 2^(-3/2)


Original post by Azx-
Yes, so basically the 2√ 2 can be split in to: 2 times 2 which in other words is times 2^1/2. Now using the power rule, we know that we need to add the indices together so 1 + 1/2 is 3/2. Now we have 1 over 2^3/2 which can be rewritten as 2^-3/2. Hope this helps.

Thank you!

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