AS Further maths mechanics and decision
Can anyone remember any answers they got for the Edexcel fm1 and d1 exam today
Here’s my answers for Further mechanics:
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
Original post by gaussian_maths
Here’s my answers for Further mechanics:
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
bro how do you remember
Original post by gaussian_maths
Here’s my answers for Further mechanics:
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
for the question with the distance as 7cm how did you get that because in the question it said d cm so i converted d cm into meters which is 0.01d meters then i did the calculation and i got d as 783 cm to 3sf as at the end you multiply by 100 to turn it back to cm I did this because height is always in meters in these calculations
Original post by gaussian_maths
Here’s my answers for Further mechanics:
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
Q travelled at 7/2 u
Velocity of the race car was 40m/s, you had to convert that to km/h though
Velocity when going uphill: 20m/s
Initial Velocity of the stone: 24m/s
Distance into the ground: 7cm
KE loss was 5mu^2(2-3e)/6
Hi, do you remember any other questions as well as their answers? If you could explain how to do them that would be great as well
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